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torisob [31]
4 years ago
12

Objects 1 has half the mass of object 2 and the objects move toward each other and experience an inelastic collision. If both ob

jects do not move after the collision compare the velocity of both objects before the collision.
Physics
1 answer:
Vika [28.1K]4 years ago
3 0

Answer:

Explanation:

Given

Object 1 is  of mass \frac{m}{2}

Object 2 has mass of m

They undergone inelastic collision and do not move after collision i.e. the collision is perfectly inelastic

Final momentum of both the object is zero

suppose v_1 and v_2 are the velocities of object 1 and 2 respectively then

m_1v_1+m_2v_2=0

\frac{v_1}{v_2}=-\frac{m_2}{m_1}

\frac{v_1}{v_2}=-2

v_1=-2v_2

i.e. velocity of object 1 is twice the velocity of object 2 but opposite to the direction of object 2

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A steel wire of length 31.0 m and a copper wire of length 16.0 m, both with 1.00-mm diameters, are connected end to end and stre
Karolina [17]

Answer

given,

steel wire length = 31 m

copper wire length = 16 m

diameter of both the wire = 1 mm = 0.001 m

Tension  = 134 N

Density of steel = 7860 kg/m³

Density of copper = 8920 kg/m³

Speed of the wave of steel wire

 v_s = \sqrt{\dfrac{T}{\dfrac{m}{l}}}

 v_s = \sqrt{\dfrac{T}{\dfrac{\rho (Al)}{l}}}

mass  =  density x volume

 v_s = \sqrt{\dfrac{T}{\rho A}}

 v_s = \sqrt{\dfrac{T}{\rho \pi \dfrac{d^2}{4}}}

 v_s = \sqrt{\dfrac{134}{7860 \pi \dfrac{0.001^2}{4}}}

v_s = 147.33 m/s

Speed of the wave of copper wire

 v_c= \sqrt{\dfrac{T}{\rho \pi \dfrac{d^2}{4}}}

 v_c = \sqrt{\dfrac{134}{8920 \pi \dfrac{0.001^2}{4}}}

v_c = 138.3 m/s

time required

 t = t_1 + t_2

 t = \dfrac{l_s}{v_s} +\dfrac{l_c}{v_c}

 t = \dfrac{31}{147.33} +\dfrac{16}{138.3}

t = 0.326

3 0
3 years ago
A 605 gram aluminum bar has the following dimensions length 0.75 m, width 0.010 m and height 0.030 m. The bar is clamp at its ce
yarga [219]

Answer:

V= 4999.5 m/s

Explanation:

Given that

mass ,m= 605 gm

Length ,L= 0.75 m

width ,b= 0.01 m

height ,h= 0.03 m

frequency ,f= 3333 Hz

We know that

2 Length = Wavelength

λ= 2 x L

λ = 2 x 0.75 m

λ= 1.5 m

The speed V

V= f x λ

Now by putting the values

V= f x λ

V= 3333 x 1.5 m/s

V= 4999.5 m/s

3 0
3 years ago
Example of natural frequency
Verizon [17]

Natural frequency is a frequency when an object hits a s surface and causes ripples or vibrations or disturbance of their nearby source. An example is throwing a stone to water. When you throw a stone, it creates a wave around the fallen stone. The water is being disturbed by the stone and creates a wave. This is a natural frequency.

7 0
4 years ago
A marble is given potential energy by being placed by a location w. When the marble is released it rolls down the track at which
tatuchka [14]

Answer:

The answer is "Location Y"

Explanation:

Please find the complete question in the attachment.

As we show in the graph when the marble rolling with the full force it will stop on the y location because it is curved, and the marble can't move to another location, that's why the maximum kinetic energy of the marble is at the y location.

4 0
3 years ago
Please check my work
Andrej [43]

Answer:

All correct

Explanation:

7 0
3 years ago
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