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svlad2 [7]
3 years ago
15

How does this level of organization relate to cells? To organ systems?

Physics
1 answer:
Setler [38]3 years ago
4 0
System is a group of similar organs working together...... Organ is a group of similar tissues forming a layer in an organism which perform a specific function.....tissue is a group of similar cell which carry out a particular function
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Two planets have the same surface gravity, but planet B has twice the mass of planet A. If planet A has mass m, what is the mass
strojnjashka [21]
If B has twice the mass the answer is 2M
5 0
2 years ago
A 1500 kg car is moving on a flat, horizontal flat road. If the radius of the curve is 35 m and
Troyanec [42]

The net force on the car is the friction that keeps it on the road, which points toward the center of the circle of the curve. Then by Newton's second law, we have

• net vertical force:

∑ <em>F</em> = <em>N</em> - <em>W</em> = 0

• net horizontal force:

∑ <em>F</em> = <em>Fs</em> = <em>m a</em>

where

<em>N</em> = magnitude of normal force

<em>W</em> = car's weight

<em>Fs</em> = mag. of static friction

<em>m</em> = car's mass

<em>a</em> = <em>v</em> ²/<em>R</em> = mag. of the centripetal acceleration

<em>v</em> = car's speed

<em>R</em> = radius of curve

Now,

• compute the car's weight:

<em>W</em> = <em>m g</em> = (1500 kg) (9.8 m/s²) = 14,700 N

• solve for the mag. of the normal force:

<em>N</em> = 14,700 N

• solve for the mag. of the friction force, using the given friction coefficient:

<em>Fs</em> = 0.5 <em>N</em> = 7350 N

• solve for the (maximum) acceleration:

7350 <em>N</em> = (1500 kg) <em>a</em>   →   <em>a</em> = 4.9 m/s²

• solve for the (maximum) speed:

4.9 m/s² = <em>v</em> ²/ (35 m)   →   <em>v</em> ≈ 13 m/s

4 0
3 years ago
A friend has written to you informing you that she/he giving him/her the name of some place in nepal
sleet_krkn [62]

Answer:

The answer is below

Explanation:

Dear Friend,

I received your letter a few days back. And because I was busy with work, I couldn't write a reply to you immediately. However, here is my well-detailed reply to your request. I hope you find it satisfactory. I am excited to learn that you wish to go on a tour to Nepal. For the advice, here is my suggestion for some places for you to visit.

1. Kathmandu: this is the capital of Nepal. It also doubles as the capital city. The atmosphere there is electric. The streets are wide and there are old monumental buildings there.

2. Bhaktapur: here you find interesting things around. It is the third-largest royal city. Durbar square is a nice place to visit.

3. Pokhara: this place has the largest population and the city is cleaner compared to most other big cities around. It has wonderful places to relax. And if you enjoy hiking this is the place for you.

4. Chitwan National Park: I know you love watching wildlife. So this is a must for you to visit. You get to see amazing animals such as rhinos, Bengal tigers, leopards, etc.

However, due to space and for me not to bore you, here are other honorable mentions

Trekking in the Langtang region, Swayambhunath, known as Monkey Temple. You should also consider the Everest & the Trek to Base Camp.

I hope you will enjoy your stay to the fullest. Don't forget to send me details of your tour after your visit.

I love you, friend.

Yours sincerely,

MyName

4 0
3 years ago
The specific heat of gold is 0.126 J/g°C. What mass of gold would change its temperature from 25.0 °C to 60.0 °C with the additi
fiasKO [112]
<span>The amount of heat energy needed to increase the temperature of a substance by </span>\Delta T<span> is given by:
</span>Q=m C_s \Delta T<span>
where m is the mass of the substance, Cs is its specific heat capacity and </span>\Delta T<span> is the increase in temperature of the substance.

In this problem, we have a certain mass m of gold, with specific heat capacity </span>C_s=0.126 J/g^{\circ}C<span>, to which we add Q=2825 J of energy. Its temperature increases by </span>\Delta T=60-25=35 ^{\circ}C<span>. Therefore, if we re-arrange the previous equation, we can find the mass of the block of gold:
</span>m= \frac{Q}{C_s \Delta T} = \frac{2825J}{0.126\cdot 35}} =641 g<span>
So, the correct answer is B.</span>
3 0
3 years ago
Read 2 more answers
A ball weighing 10 kg rolls down a frictionless incline with a 50 degree angle to the horizontal. if the balls initial velocity
Marat540 [252]
The answer is the third one
8 0
2 years ago
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