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svlad2 [7]
3 years ago
15

How does this level of organization relate to cells? To organ systems?

Physics
1 answer:
Setler [38]3 years ago
4 0
System is a group of similar organs working together...... Organ is a group of similar tissues forming a layer in an organism which perform a specific function.....tissue is a group of similar cell which carry out a particular function
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ILL MARK BRAINLIEST
77julia77 [94]

Answer: B

Longitudinal wave

Explanation:

Transverse waves have crests and troughs

Longitudinal waves have compressions and rarefactions. A compression is where the density of the wave medium is highest. While a rarefaction is where the density of the wave medium is lowest.

Since sound wave is a longitudinal wave. And longitudinal wave exists apart from sound, we can therefore conclude that it's a longitudinal wave in spring.

8 0
3 years ago
Sensory receptors pick up on senses from outside the body. To respond to the sense, what path does the information follow?
Radda [10]

Answer:

Follow that smell. SMELL: Originally thought to be present only in the nose, olfactory receptors exist in many locations in the body, including in the skin, heart, lungs, kidneys, muscles, and sperm. ...

Light relaxation. ...

A taste for pathogens

Explanation:

please mark me brainliest.

7 0
3 years ago
Read 2 more answers
A positive charge is placed in an electric field that points west. What direction is the force on the positive particle? I think
Kisachek [45]
Right.  You are true.  The direction of the electric field is defined to be
the direction of the force on a small positive charge placed in the field.
3 0
4 years ago
The ink drops have a mass m = 1.00×10^−11 kg each and leave the nozzle and travel horizontally toward the paper at velocity v =
luda_lava [24]

Answer:

9.98 × 10⁻⁹ C

Explanation:

mass, m = 1.00 × 10⁻¹¹ kg

Velocity, v = 23.0 m/s

Length of plates D₀ = 1.80 cm = 0.018 m

Magnitude of electric field, E = 8.20 × 10⁴ N/C

drop is to be deflected a distance d = 0.290 mm = 0.290 × 10⁻³ m

density of the ink drop = 1000 kg/m^3

Now,

Time = \frac{\textup{Distance}}{\textup{Velocity}}

or

Time = \frac{\textup{0.016}}{\textup{23}}

or

Time = 6.9 × 10⁻⁴ s

Now, force due to the electric field, F = q × E

where, q is the charge

Also, Force = Mass × acceleration

q × E = 1.00 × 10⁻¹¹ × a

or

a = \frac{q\times8.20\times10^4}{1\times10^{-11}}

Now from the Newton's equation of motion

d=ut+\frac{1}{2}at^2

where,  

d is the distance

u is the initial speed  

a is the acceleration

t is the time

or

0.290\times10^{-3}=0\times(6.9\times10^{-4})+\frac{1}{2}\times(\frac{q\times8.20\times10^4}{1\times10^{-11}})\times(6.9\times10^{-4})^2

or

q = 9.98 × 10⁻⁹ C

4 0
3 years ago
What current flows through a 2.56-cm-diameter rod of pure silicon that is 20.0 cm long, when 1.00 ✕ 103 V is applied to it? (Suc
vfiekz [6]

Answer:

Current, I = 0.0011 A

Explanation:

It is given that,

Diameter of rod, d = 2.56 cm

Radius of rod, r = 1.28 cm = 0.0128 m

The resistivity of the pure silicon, \rho=2300\ \Omega-m

Length of rod, l = 20 cm = 0.2 m

Voltage, V=1\times 10^3\ V

The resistivity of the rod is given by :

R=\rho\dfrac{L}{A}

R=2300\ \Omega-m\dfrac{0.2\ m}{\pi (0.0128\ m)^2}

R = 893692.30 ohms

Current flowing in the rod is calculated using Ohm's law as :

V = I R

I=\dfrac{V}{R}

I=\dfrac{10^3\ V}{893692.30\ \Omega}

I = 0.0011 A

So, the current flowing in the rod is 0.0011 A. Hence, this is the required solution.

6 0
3 years ago
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