Answer:
ΔP = 986 Kpa
Explanation:
The solution is given in the pictures below
Answer:
The two objects will collide with the same position vector for all three components at exactly t = 4 s
Explanation:
For two particles starting out at the same time to collide, their position Vector's at the time of collision must be exactly the same.
So, at the collision point, position vector of object 1 is equated to that of object 2.
r₁ = (t², 13t-36, t²)
r₂ = (7t-12, t², 5t-4)
At he point of collision
t² = 7t - 12
t² - 7t + 12 = 0
t² - 4t - 3t + 12 = 0
t(t - 4) - 3(t - 4) = 0
t = 3s or t = 4s
13t - 36 = t²
t² - 13t + 36 = 0
t² - 4t - 9t + 36 = 0
t(t - 4) - 9(t - 4) = 0
t = 9s or 4s
t² = 5t - 4
t² - 5t + 4 = 0
t² - 4t - t + 4 = 0
t(t - 4) - 1(t - 4) = 0
t = 1s or t = 4s
The three components intersect at other times, but at t = 4s, they all intersect at the same time! Meaning that, at this point the two objects are at the same place with the same position vector at that time.
<u>Answer:</u>
Work done done by a system on its environment is W=40 Joules
<u>Explanation:</u>
<u>Given:</u>
Ideal gas is maintained at a constant pressure 
Change in Volume 
<u>To find:</u>
Work done by a system during an Isobaric Process
<u>Solution:</u>
In a Isobaric Process, constant pressure is maintained,
According to the formula,
work done 
Substitute the values of pressure and change in volume in the above formula,
<u>Result:</u>
Work done done by a system W= -40 Joules
Answer:
It is showing the wavelength.
Explanation: Hope it helps you:)))
have a good day
Build up of pressure between tectonic plates .
