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kupik [55]
3 years ago
5

How does electrical energy differ from electromagnetic energy?

Physics
1 answer:
xenn [34]3 years ago
7 0

Answer:

Electric energy is all about seperation of opposite charges and bringing similar charges together. ... Electromagnetic energy is energy in an electromagnetic wave, thus it is not associated with any particular charge it is in the oscillating fields themselves (Electric and Magnetic fields)

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zanele has a mass of 40kg and is sitting inside a 20kg cart .zanele's friends pull a cart with a force of 500N at an angle of 20
Dmitriy789 [7]

The net horizontal force acting on the cart is 169.85 N.

The change in the carts momentum is 5,000 Ns.

The net horizontal force on Zanele is same as the net horizontal force on the cart.

If angle between the 500N force and the horizontal is decreased, the final velocity of the cart increases.

The given parameters:

  • Mass of zanele, m1 = 40 kg
  • Mass of the cart, m2 = 20 kg
  • Applied force, F = 500 N, at angle 20 degrees
  • Frictional force on the cart, Ff = 300 N
  • Time, t = 10 s

<h3>Net horizontal force on the cart;</h3>
  • The net horizontal force acting on the cart is calculated as follows;

F_{net} = F - F_f\\\\F_{net} = 500 \times cos(20) - 300\\\\F_{net} = 169.85 \ N

<h3>Change in momentum;</h3>
  • The change in the carts momentum at the given time of applied force is calculated as follows;

\Delta mv = Ft  \\\\\Delta mv = 500 \times 10= 5,000 \ Ns

The net horizontal force on Zanele is same as the net horizontal force on the cart.

<h3>The final velocity of the cart;</h3>
  • When the angle decreases the cart's final velocity would be affected  as follows;

F_{net} = F - F_f\\\\F_{net} = \frac{mv}{t} \\\\\frac{mv}{t} =  F - F_f\\\\  \frac{mv}{t} =  Fcos(\theta) - F_f\\\\let \ \theta  = 0^0\\\\\frac{mv}{t} =500 \times cos(0) - 300\\\\\frac{mv}{t} = 200\\\\v = \frac{200 t}{m} \\\\when \ \theta = 20^0\\\\\frac{mv}{t} =500 \times cos(20) - 300\\\\\frac{mv}{t} = 169.85\\\\v = \frac{169.85t}{m}

Thus, if angle between the 500N force and the horizontal is decreased, the final velocity of the cart increases.

Learn more about net horizontal force here: brainly.com/question/21684583

5 0
3 years ago
Given uranium 235 go through an alpha, beta, beta, alpha, gamma, neutron and alpha. What do you have now?
Licemer1 [7]

Answer:

b. 88, 222

Explanation:

235U₉₂ ----→ Alpha --------→  231P₉₀  ----→- beta -----→ 231Q₉₁ ------→-beta -------→231R₉₂--------→-alpha ------→-227S₉₀ ------→ gamma -----→-227S₉₀ ----------→ neutron ------→-226T₉₀-----------→ alpha --------→222 X ₈₈

Atomic No is 88 , atomic weight = 222 .

3 0
3 years ago
. A bird is flying with a speed of 18.0 m/s over water when it accidentally drops a 2.00 kg fish. If the altitude of the bird is
zysi [14]
V^2 = u^2 + 2gr, where v - speed, u - initial speed=0, r - displacement (or height)
v^2 = 0 + 2*10*5.4
v = 10.2 m/s
4 0
3 years ago
Read 2 more answers
The acceleration of gravity is a constant equal to _______ meters per second squared.
VLD [36.1K]
B. 9.8.
is the Answer
5 0
3 years ago
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Calculate the electric field associated to an electric dipole for two charges separated 10-8 m with a dipole moment of 10-33 C m
Alex Ar [27]

Answer:

18 N/C

Explanation:

Given that:

Electric field constant, k = 9*10^9 N/c

Distance, r = 10^-8 m

Dipole moment, p = 10^-33

Using the relation for electric field due to dipole :

E = [2KP / r³]

E = (2 * (9*10^9) * 10^-33) ÷ (10^-8)^3

E = (18 * 10^9 * 10^-33) ÷ 10^-24

E = [18 * 10^(9-33)] ÷ 10^-24

E = (18 * 10^-24) / 10^-24

E = 18 * 10^-24+24

E = 18 * 10^0

E = 18 N/C

5 0
3 years ago
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