Which expression is equivalent to 8-(6r+2) -6r+6 2r+2 6r+10 -6r+10
1 answer:
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Answer:
The equation of line passing through point (2 , 2) and perpendicular to line y = x is y = - x + 4 .
Step-by-step explanation:
Given as :
The line equation is y = x
Now, equation of line in slope-intercept form y = m x + c
where m is the slope of line and c is y-intercept
Comparing given line equation with standard line equation
The slope of line y = x is m = 1
Again
Other line is passing through point (2 ,2) and is perpendicular to line y = x
Let The slope of other line = M
∵ From perpendicular lines property
Product of slope of lines = - 1
i.e m × M = - 1
Or , M =
Or, M =
∴ M = - 1
<u>Now, Equation of other line in point-slope form</u>
The other line is passing through point (2 , 2) and slope M = - 1
So, y - = M × (x -
)
Or, y - 2 = - 1 × ( x - 2 )
Or, y - 2 = - x + 2
Or, y = - x + 2 + 2
Or, y = - x + 4
Hence, The equation of line passing through point (2 , 2) and perpendicular to line y = x is y = - x + 4 . Answer
<h3>Answer: Choice H) 2</h3>
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Explanation:
Recall that the pythagorean trig identity is
If we were to isolate sine, then,
We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.
Through similar calculations,
Cosine is also positive in this quadrant.
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So,
Therefore,
is an identity as long as 0 < x < pi/2