10) because of the alternative exterior angle theorem angle 2 is the same as angle 8 and because of the vertical angles congruence theorem angles 2 and 4 are also the same so if angle 2 is the same as both 4 and 8,
then x=5 because 4x+57 =77
subtract 57 from both sides and 4x=20
divide both sides by 4 and x equals 5
-1 < c + 2 < 3....subtract 2 from all sections
-1 - 2 < c + 2 - 2 < 3 - 2...simplify
-3 < c < 1
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32 > 16 - 4g > 12....subtract 16 from all sections
32 - 16 > 16 - 16 - 4g > 12 - 16....simplify
16 > -4g > -4 ...now divide all sections by -4, and change inequality signs
16/-4 < (-4/-4)g < -4/-4...simplify
-4 < g < 1
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6y + 1 > = 10
6y > = 10 - 1
6y > = 9
y > = 9/6 which reduces to 3/2 or 1 1/2
-3/2y > = 9 ....multiply both sides by -2/3, cancelling the -3/2 on the left...and change the inequality sign
y < = 9 * -2/3
y < = -18/3 which reduces to - 6
so y > = 9/6(or 1 1/2) or y < = -6
Answer:
2nd graph above the one you chose
Answer:
1,800
Step-by-step explanation:
Answer: (y^2-a)(1+x-b)
Step-by-step explanation:
Factor out the common terms: =x(y^2-a)-by^2+ab+y^2-a
Then rewrite as: =(y^2-a)x-by^2+ab+1 x (y^2-a)
Factor out the common term (y^2 - a): =(y^2-a)(x+1)-by^2+ab
Factor out the common term b: =(y^2-a)(1+x)+b(-y^2+a)
Rewrite as: =(y^2-a)(1+x)-(y^2-a)b
Factor out the common term (y^2 - a): =(y^2-a)(1+x-b)
