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3 years ago

Given QC midpoint V. If Q is at (4,-11) and V is at (-9,1) what are the C coordinates

Mathematics

1 answer:

tester [92]3 years ago

6 0

Answer:

(-13,12)

Step-by-step explanation:

So, first, you make two separate equations.

4 + x = -9 (The 4 is from Q and the -9 is from V)

-11 + y = 1 (The -11 is from Q and the 1 is from V)

Then, you subtract 4 from both sides on the first one, and subtract -11 from both sides on the second one.

You should get:

x = -13

y = 12

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Answer:

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Step-by-step explanation:

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3 years ago

The yellow boxes on the bottom are the answers. Please help TYSM

sveticcg [70]

Answer:

$1.\ 8p = 64, p =8$

$2. -\dfrac{w}{4} = 8, w = -32$

$3. -5c = -20, c =4$

$4.\ 9m=45, m = 5$

$5. \dfrac{b}{25} = -3, b =-75$

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Step-by-step explanation:

Now let us see the detailed solution of each part:

Part 1:

$8p -15 = 49\\\Rightarrow 8p =49+15\\\Rightarrow 8p = 64\\\Rightarrow p =8$

Part 2:

$\dfrac{-w}{4}+18=26\\\Rightarrow \dfrac{-w}{4} = 26-18\\\Rightarrow \dfrac{-w}{4} = 8\\\Rightarrow -w = 8 \times 4\\\Rightarrow w =-32$

Part 3:

$-5c-15=-35\\\Rightarrow -5c = -35 +15\\\Rightarrow -5c = -20\\\Rightarrow c = 4$

Part 4:

$9m +10=55\\\Rightarrow 9m =55-10\\\Rightarrow 9m =45\\\Rightarrow m =5$

Part 5:

$\dfrac{b}{25}-83=-86\\\Rightarrow \dfrac{b}{25} = -86 +83\\\Rightarrow \dfrac{b}{25} = -3\\\Rightarrow b = -75$

Part 6:

$\dfrac{d}{-2}+85=105\\\Rightarrow \dfrac{d}{-2} = 105-85\\\Rightarrow \dfrac{d}{-2} = 20\\\Rightarrow d=20 \times -2\\\Rightarrow d =-40$

Please refer to attached image for the answers.

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3 years ago

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