Answer:
Initial rate of reaction is 
.
Explanation:
It is a second order reaction.
Initial rate of reaction = ![k[O_{3}]_{0}[NO]_{0}](https://tex.z-dn.net/?f=k%5BO_%7B3%7D%5D_%7B0%7D%5BNO%5D_%7B0%7D)
, where k is rate constant, ![[O_{3}]_{0}](https://tex.z-dn.net/?f=%5BO_%7B3%7D%5D_%7B0%7D)
is the initial concentration of 
and ![[NO]_{0}](https://tex.z-dn.net/?f=%5BNO%5D_%7B0%7D)
is the initial concentration of NO.
Here, k = 
, ![[O_{3}]_{0}=5.84\times 10^{-6}M](https://tex.z-dn.net/?f=%5BO_%7B3%7D%5D_%7B0%7D%3D5.84%5Ctimes%2010%5E%7B-6%7DM)
and ![[NO]_{0}=8.65\times 10^{-5}M](https://tex.z-dn.net/?f=%5BNO%5D_%7B0%7D%3D8.65%5Ctimes%2010%5E%7B-5%7DM)
So, initial rate of reaction = 
=
So, initial rate of reaction is
Thank you for the free 15 points .
The two systems would be respiratory and circulatory i think not completely sure tho <span />
<span>10% of the 25% of people that prefer to swim on weekends are female.
Multiply 10% and 25% to get 0.025
</span><span> 55% of the 75% are females who prefer to swim on the weekdays.
Multiply them together getting 0.4125
</span>
<span>Divide 0.25 by 0.10= 0.40</span>
