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xxTIMURxx [149]
3 years ago
11

H₃C-Ç=CCH₃сна сHз (what is the name of this chemical formula)​

Chemistry
1 answer:
algol [13]3 years ago
3 0

Answer:2,3 -dimethyl-2-butenr

Explanation:

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Which of the following energy quantities is equivalent to 578 J?
svlad2 [7]

Answer:

  • <em>0.138 kcal</em>

Explanation:

The answer choices are:

  • a) 5.78 × 10⁵ kJ
  • b) 138 kcal
  • c)0.138 kcal
  • d)1.38 × 10⁵ kcal

<h2>Solution</h2>

You must use the conversion factors to convert J to kcal.

  • 1cal = 4.184J

        Dividing both sides by 4.184J:

        ⇒ 1 = 1cal/4.184J

  • 1kcal = 1,000cal

       Dividing both sides by 1,000 cal

        ⇒ 1 = 1kcal / 1,000 cal

Mutiply<em> 578J</em> by the conversion factors to find <em>kcal</em>:

       578J\times 1cal/4.184J\times 1kcal/1,000cal=0.138kcal

Notice how the units J and cal cancel to yield kcal at the end.

5 0
3 years ago
How many molecules are in 20.0 L(liters) of SO2 at STP
Finger [1]

5.4 x 10²³ molecules

Explanation:

Given parameter

Volume of gas = 20L

Condition of reaction = STP

Unknown:

number of molecules

Solution:

The number of molecules of a substance is given by;

   Number of molecules = Number of moles x avogadro's constant

Number of moles at stp = \frac{volume of gas}{22.4}

 Number of moles of SO₂ = \frac{20}{22.4} = 0.893mole

Number of molecules = 0.893 x 6.02 x 10²³ = 5.4 x 10²³ molecules

learn more:

Number of molecules brainly.com/question/10818009

#learnwithBrainly

4 0
3 years ago
helppppp. which of the following statements regarding physical and chemical changes is true? a. both physical and chemical chang
jasenka [17]

Answer:

D. chemical alters the atomic structure of a substance, while physical does not

hope this helps!

4 0
3 years ago
Read 2 more answers
How many moles of H2O are in 36 grams of water?
saw5 [17]

Answer:

2 moles

Explanation:

number of mole =mass /molar mass

mass=36

molar mass=(2*1)+16=18

therefore, no of mole =36÷18 =2

4 0
3 years ago
There are a few different shapes of airplanes being considered in the design of a new airplane. One design would add protrusions
Ede4ka [16]

C. The design would not be cost-efficient; the plane would require more fuel due to increased thrust from higher drag.

7 0
4 years ago
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