. Which type of energy is involved in the operation of simple machines?

Calculate the molarity of a solution prepared by dissolving 11.9 g of beryllium chloride in a total volume of 292.2 mL of soluti

anyanavicka [17]

Answer:

8793

Explanation:

8 0

3 years ago

A chemist must dilute 97.1 ml of aqueous magnesium fluoride solution until the concentration falls to 389 microMolarity . He'll

mojhsa [17]

Answer:

0.302L

Explanation:

...97.1mL of 1.21m M aqueous magnesium fluoride solution

In this problem the chemist is disolving a solution from 1.21mM = 1.21x10⁻³M, to 389μM = 389x10⁻⁶M. That means the solution must be diluted:

1.21x10⁻³M / 389x10⁻⁶M = 3.11 times

As the initial volume of the original concentration is 97.1mL, the final volume must be:

97.1mL * 3.11 = 302.0mL =

0.302L

6 0

3 years ago

What amount if force need to be applied to a 20 kg bowling ball to give it an acceleration of 5m/s

balandron [24]

Answer:

100N

Explanation:

Given parameters:

Mass of the bowling ball = 20kg

Acceleration = 5m/s²

Unknown:

Amount of force applied = ?

Solution:

To solve this problem, we apply newton's second law of motion.

Force = mass x acceleration

Now insert the parameters and solve;

Force = 20 x 5 = 100N

5 0

3 years ago

What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?

AlladinOne [14]

The question is incomplete, here is the complete question:

The given chemical reaction is:

$2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3$

What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?

Answer: The theoretical yield of copper is 44.48 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of aluminium = 12.6 g

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

$\text{Moles of aluminium}=\frac{12.6g}{27g/mol}=0.467mol$

The given chemical equation follows:

$2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3$

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of copper

So, 0.467 moles of aluminium will produce = $\frac{3}{2}\times 0.467=0.7005mol$ of copper

Now, calculating the mass of copper from equation 1, we get:

Molar mass of copper = 63.5 g/mol

Moles of copper = 0.7005 moles

Putting values in equation 1, we get:

$0.7005mol=\frac{\text{Mass of copper}}{63.5g/mol}\\\\\text{Mass of copper}=(0.7005mol\times 63.5g/mol)=44.48g$

Hence, the theoretical yield of copper is 44.48 grams

4 0

3 years ago

The amount of matter in a object is referred as:

mestny [16]

Volume is the thing
…………….

4 0

3 years ago