Twice the sum of a number and 3
2 (x+3)
is the same
=
as 11 increased by the number
11 + x
so...
2 (x+3) = 11 + x
2x+6 = 11+x
2x-x = 11-6
x = 5
R u sure there Is no more to the question? I feel like there is a missing number somewhere :)
X - 26000 - .06(26000) = 11,600
x - 26,000 - 1560 = 11,600
x - 27560 = 11,600
x = 11,600 + 27,560
x = 39,160 <== selling price
Answer:
3 m^2
Step-by-step explanation:
The shaded area = Area of Sector - Area of Triangle
First we find area of sector = ![\frac{\theta}{360}*\pi r^2](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctheta%7D%7B360%7D%2A%5Cpi%20r%5E2)
<em>We know the angle is 60° (vertical angles are equal) and the radius is 6, so we find the area of sector to be:</em>
![\frac{\theta}{360}*\pi r^2\\\frac{60}{360}*\pi (6)^2\\=18.85](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctheta%7D%7B360%7D%2A%5Cpi%20r%5E2%5C%5C%5Cfrac%7B60%7D%7B360%7D%2A%5Cpi%20%286%29%5E2%5C%5C%3D18.85)
Secondly, we find area of triangle (isosceles) = ![\frac{1}{2}abSinC](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DabSinC)
where
a and b are the two sides bordering the known angle, so a=b=6, and
C is the angle which is <em>60°</em>
Now we find the area to be:
![\frac{1}{2}(6)(6)Sin(60)\\=15.59](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%286%29%286%29Sin%2860%29%5C%5C%3D15.59)
Hence, area of shaded = ![18.85 - 15.59=3.26](https://tex.z-dn.net/?f=18.85%20-%2015.59%3D3.26)
Rounding to nearest whole number, area of shaded region = 3m^2
Hope this helps lozzzzzzs