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Andrews [41]
3 years ago
12

Can I have help? I'll mark you!

Mathematics
2 answers:
Taya2010 [7]3 years ago
6 0

Answer:

1,2,6 :)

Step-by-step explanation:


svlad2 [7]3 years ago
3 0

1, 2 and 6 are right.

Solution go on infinitely

all solution are negative because its number less than -20

solution contain rational among others

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2sec^2x - secx - 1 = 0
Ivenika [448]
What are you trying to do here?
Solve the graph, or make it appear as something else?

First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0

sec (x) (2sec (x) -2) = 0


Then we're going to separate the two to find the zeros of each because anything time 0 is zero.

sec(x) = 0

2sec (x) - 2 = 0

Now, let's simplify the second one as the first one is already.

Add 2 to both sides:

2sec (x) = 2

Divide by 3 on both sides:

sec (x) = 1


I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
8 0
3 years ago
Simplify if possible
Anarel [89]
The answer is the last choice 2 1/2
8 0
3 years ago
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PLEASE HELP!! if f(x)= 2x^2-11, find f(4)
Lemur [1.5K]

Answer: f(4) = 21

Step-by-step explanation:

2(4)^2-11

4^2 = 16

2(16)-11

Multiply 2 and 16

32 - 11

Subtract

21

4 0
3 years ago
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Which equation is parallel to the line LaTeX: y=\frac{1}{2}x+3y = 1 2 x + 3and passes through the point (10, -5)?
sukhopar [10]

Answer:

Equation\ of\ line:\ y=\frac{1}{2}x-10

Step-by-step explanation:

Let\ the\ required\ equation\ is\ y=mx+c\\\\where\ m\ is\ the\ slope\ of\ the\ equation\ and\ c\ is\ y-intercept\\\\It\ is\ parallel\ to\ the\ equation\ y=\frac{1}{2}x+3\\\\Hence\ slope\ of\ these\ two\ lines\ will\ be\ same.\\\\Slope\ of\ y=\frac{1}{2}x+3\ is\ \frac{1}{2}\\\\Hence\ slope\ of\ y=mx+c\ is\ \frac{1}{2}\Rightarrow m=\frac{1}{2}\\\\Equation:y=\frac{1}{2}x+c\\\\Line\ passes\ through\ (10,-5).\ Hence\ this\ point\ satisfies\ the\ equation\ of\ line.\\\\-5=\frac{1}{2}\times 10+c

-5=-5+c\\\\c=-10

Equation\ of\ line:\ y=\frac{1}{2}x-10

8 0
2 years ago
Question in image again
Reil [10]
16in I believe irdk
Hope it helped..
7 0
2 years ago
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