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Alchen [17]
3 years ago
9

He says that the plotted point is (0.5,0.25). What is Hassan's error?

Mathematics
2 answers:
Crank3 years ago
3 0
Both Coordinates should be negative
aliina [53]3 years ago
3 0
The correct answer would be both coordinates should be negative :)
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Which graph represents (x - 1)2/9 (y-3)2/1
Marat540 [252]
We can only see one graph here
7 0
2 years ago
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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
Read 2 more answers
In Mr. Hamilton's classroom, there are 16 supply boxes in the cabinet. Each supply box
gulaghasi [49]

Answer:

12

Step-by-step explanation:

192/16=12

5 0
3 years ago
Please answer according to the picture.
katen-ka-za [31]
-4 and 2 are the solutions, since that is where they intercept the x axis, and when plugged into the equation, make it true.
6 0
3 years ago
A company used 7.4 x 105 sheets of paper a month, the accounting department used 8.9 x 103 sheets. How many were used by other d
seraphim [82]

Answer:

731,100

7.311 × 10^5

Step-by-step explanation:

The computation of the number of sheet used by other department is given below:

Given  that

The company used 7.4 × 10^5 sheets of paper So it would be 740,000  

And, The accounting department used 8.9 × 10^3 sheets so it would be 8,900  

Now the number of sheet used by other department is

= 740,000 - 8,900

= 731,100

= 7.311 × 10^5

4 0
2 years ago
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