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Paladinen [302]

3 years ago

13

Pat picked a card from a standard deck, looked at it, and then put it back. He then picked a second card. What is the probabilit

y that Pat pick a diamond or a jack on either pick

1 answer:

AlekseyPX3 years ago

3 0

Answer: 17/52

Step-by-step explanation:

There are 52 total cards in a standard deck.

The number of diamonds in a deck of cards is 13 and there are 4 jacks in a deck of cards.

So the propabibilty of Pat picking a diamond is 13/52 and the probability of Pat picking a jack is 4/52. Now you have to add the two probabilities together.

You do not remove any digits because Pat put the card back into the deck, he didn't take it away. So we do not take away from the total

13 + 4 = 17

You do not need to change the denominator cause 52 is the same.

So 17/52 is the probability of Pat picking a diamond or a jack

I hope this helped!

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What is the most precise name for a quadrilateral with the following vertices:

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The most precise name for a quadrilateral ABCD is a parallelogram

Step-by-step explanation:

we have

A(2,3) B(7,2) C(6,-1) D(1,0)

Plot the quadrilateral'

using a graphing tool

The quadrilateral ABCD in the attached figure

Verify the length of the sides

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find distance AB

A(2,3) B(7,2)

substitute

$d=\sqrt{(2-3)^{2}+(7-2)^{2}}$

$d=\sqrt{(-1)^{2}+(5)^{2}}$

$d_A_B=\sqrt{26}\ units$

step 2

Find distance BC

B(7,2) C(6,-1)

substitute

$d=\sqrt{(-1-2)^{2}+(6-7)^{2}}$

$d=\sqrt{(-3)^{2}+(-1)^{2}}$

$d_B_C=\sqrt{10}\ units$

step 3

Find distance CD

C(6,-1) D(1,0)

substitute

$d=\sqrt{(0+1)^{2}+(1-6)^{2}}$

$d=\sqrt{(1)^{2}+(-5)^{2}}$

$d_C_D=\sqrt{26}\ units$

step 4

Find distance AD

A(2,3) D(1,0)

substitute

$d=\sqrt{(0-3)^{2}+(1-2)^{2}}$

$d=\sqrt{(-3)^{2}+(-1)^{2}}$

$d_A_D=\sqrt{10}\ units$

step 5

Compare the length sides

AB=CD

BC=AD

Opposite sides are congruent

<em>Verify the slope of the sides</em>

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find slope AB

A(2,3) B(7,2)

substitute

$m=\frac{2-3}{7-2}$

$m=\frac{-1}{5}$

$m_A_B=-\frac{1}{5}$

step 2

Find slope BC

B(7,2) C(6,-1)

substitute

$m=\frac{-1-2}{6-7}$

$m=\frac{-3}{-1}$

$m_B_C=3$

step 3

Find slope CD

C(6,-1) D(1,0)

substitute

$m=\frac{0+1}{1-6}$

$m=\frac{1}{-5}$

$m_C_D=-\frac{1}{5}$

step 4

Find slope AD

A(2,3) D(1,0)

substitute

$m=\frac{0-3}{1-2}$

$m=\frac{-3}{-1}$

$m_A_D=3$

step 5

Compare the slopes

$m_A_B=m_C_D$

$m_B_C=m_A_D$

The slope of the opposite sides are equal, that means, opposite sides are parallel

The slopes of consecutive sides are not opposite reciprocal, that means, consecutive sides are not perpendicular

therefore

The most precise name for a quadrilateral ABCD is a parallelogram

8 0

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