Answer:
The answer is explained below
Step-by-step explanation:
The question is not complete we need point P and point Q.
let us assume P is at (3,1) and Q is at (-2,4)
To find the coordinate of the point that divides a line segment PQ with point P at and point Q at
in the proportion a:b, we use the formula:
line segment PQ is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:
Answer:
0.4
Step-by-step explanation:
Given:-
- The uniform distribution parameters are as follows:
a = $10,000 b = $15,000
Find:-
Suppose you bid $12,000. What is the probability that your bid will be accepted?
Solution:-
- We will denote a random variable X that defines the bid placed being accepted. The variable X follows a uniform distribution with parameters [a,b].
X ~ U(10,000 , 15,000)
- The probability of $12,000 bid being accepted can be determined by the cdf function of the uniform distribution, while the pmf is as follows:
Pmf = 1 / ( b - a )
Pmf = 1 / ( 15,000 - 10,000 )
Pmf = 1 / ( 5,000 )
Answer:
The volume of rectangular box is 9,000 cubic centimeters
Step-by-step explanation:
Given as :
The length of the rectangular sheet = L = 62 cm
The width of the rectangular sheet = B = 42 cm
Let The volume of rectangular box = v cubic centimeters
From each corner of sheet a square of 6 cm is cut out and an open box made
So, The length of box = L' = (L - 6 - 6)
i.e L' = (62 - 6 - 6)
Or, L' = 50 cm
Or, Length of the box = 50 cm
And The width of the box = B' = (B - 6 - 6)
i.e B' = (42 - 6 - 6)
Or, B' = 30 cm
Or width of the box = 30 cm
And,
The height of the box = H = 6 cm
∴ volume of rectangular box = Length of box × Breadth of box × Height of box
i.e v = L' × B' × H
Or, v = 50 cm × 30 cm × 6 cm
Or, v = 9,000 cm³
So, The volume of rectangular box = v = 9,000 cm³
Hence, The volume of rectangular box is 9,000 cubic centimeters Answer
