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3 years ago

I need help on all these, plss !!

Mathematics

1 answer:

dolphi86 [110]3 years ago

3 0

Answer:

8a) 100,90,110,70, 130

8b) 110, 100,120,80,140

8c)110

8d) Once you added 10 to each number the mean had a value of +10

8e) Make 8 points higher on each test.

Step-by-step explanation:

Hope this helps and have a great day!!

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Simplify the variable expression by evaluating its numerical part.

Virty [35]

You can use this one app it’s called Cymath it’s really helpful with these types of problems,

6 0

3 years ago

A cutting tool fails due to flank wear while machining. It is observed that the tool life at a cutting speed of 160 m/min is 5 m

Ahat [919]

Answer:

The answer is:

30 minutes.

Step-by-step explanation:

We are given the following information:

at 160 m/min, tool life = 5 min.

at 120 m/min, tool life = 17 min.

This means that as the speed reduced from 160 m/min to 120 m/min, the tool life increased from 5 min. to 17 min, hence the difference between the changes are:

speed = 160 - 120 = 40 m/min

tool life = 17 - 5 = 12 min.

Therefore, it can be concluded that a change of speed of 40 m/min, increases the tool life by 12 min.

40 m/min = 12 min

∴ 1 m/min = 12/40 min.

∴ 100 m/min = 12/40 × 100 = 0.3 × 100 =30 min.

8 0

3 years ago

Expand and simplify 4(x-2)+7(x-1)

Zolol [24]

Answer:

11x-15

Step-by-step explanation:

4x-8+7x-7

11x-15

5 0

3 years ago

Pls tell me some answers for this

devlian [24]

Answer:

∠B ≈ 56.25°

Step-by-step explanation:

Since the triangle is right use the cosine ratio to solve for B

cosB = $\frac{adjacent}{hypotenuse}$ = $\frac{BC}{AB}$ = $\frac{5}{9}$ , thus

B = $cos^{-1}$ ( $\frac{5}{9}$ ) ≈ 56.25°

3 0

3 years ago

Read 2 more answers

I'M OFFERING 20 POINTS-

Dafna11 [192]

Answer:

Third option is correct. Scale factor 3 ; enlargement.

Step-by-step explanation:

It is given that the figure A'B'C'D' is a dilation of figure ABCD.

We know that after dilation the corresponding sides of image and preimage are in the same proportion.

The image of AD is A'D'.

From the figure it is noticed that the A(-1,2), D(-1,-1), A'(-3,6) and D'(-3,-3).

Distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AD=\sqrt{(-1+1)^2+(-1-2)^2}=\sqrt{9}=3$

$A'D'=\sqrt{(-3+3)^2+(-3-6)^2}=\sqrt{81}=9$

Scale factor is constant which represents the relation between image and preimage.

$k=\frac{A'D'}{AD}$

$k=\frac{9}{3}$

$k=3$

Therefore the scale factor is 3.

If k>0 it means enlargement and if k<0 it means reduction. Therefore third option is correct.

3 0

4 years ago

Read 2 more answers

I need help on all these, plss !!​

I need help on all these, plss !!