Question

The student council is sponsoring a concert as a fundraiser. Tickets are $3 for students and $5 for adults. The student council wants to raise at least $1,000. If 200 students attend how many adults must attend for them to get to their goal. write and solve an inequality

Answer 1

Answer:

There must attend at least 80 adults to raise at least $1,000.

Step-by-step explanation:

Givens

• Tickets are $3 for students and $5 for adults.
• They want to raise at least $1,000. (Restriction).
• 200 students attended.

Let's call $S$ students and $A$ adults.

We know the benefits are restricted as

$3S+5A\geq 1000$

Because, they want to raise AT LEAST $1000, that's the minimum amount possible.

Now, we know that $S=200$, replacing this value and solving for adults, we have

$3S+5A\geq 1000\\3(200)+5A\geq 1000\\600+5A\geq 1000\\5A\geq 1000-600\\5A\geq 400\\A \geq \frac{400}{5}\\ A\geq 80$

Therefore, there must attend at least 80 adults to raise at least $1,000.

Answer 2

3S+5A≥1000
3(200)+5A≥1000
600+5A≥1000
-600        -600
5A≥400
-----------
      5

A≥80
so 80 adults