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Oksana_A [137]
3 years ago
5

#1: What did Robert Millikan's oil drop experiment prove?

Physics
1 answer:
Vilka [71]3 years ago
7 0
<span>Robert Millikan,in 1909,performed and experiment known as oil drop experiment.
During his experiment he made certain calculations and conclusions.One of them was that he determined the size of charge on an electron.</span><span>He also proved that the charge was smallest 'unit' , or simply the charge is 'quantized'.
He was also awarded with Noble prize.
So,from the above explanation,i have concluded that the best option which refers to the question asked is :
</span><span>B. It determined the actual mass of the electron.</span>
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Answer:

F= 4788 N

Explanation:

Because the car moves with uniformly accelerated movement we apply the following formula:

vf²=v₀²+2*a*d Formula (1)

Where:  

d:displacement in meters (m)  

v₀: initial speed in m/s    

vf: final speed in m/s  

a: acceleration in m/s²

Data

d=36.9 m

v₀=14.0 m/s m/s    

vf= 0  

Calculating of the acceleration of the car

We replace dta in the formula (1)

vf²=v₀²+2*a*d

(0)²=(14)²+2*a*(36.9)

-(14)²= (73.8) *a

a= - (196) /  (73.8)

a= - 2.66 m/s²

Newton's second law of the car in direction  horizontal (x):

∑Fx = m*ax Formula (2)

∑F : algebraic sum of the forces in direction x-axis (N)

m : mass (kg)

a : acceleration  (m/s²)

Data

m=1800 Fkg

a= - 2.66 m/s²

Magnitude of the horizontal net force (F) that is required to bring the car to a halt in a distance of 36.9 m :

We replace data in the formula (2)

-F= (1800 kg) * ( -2.66 m/s² )

F= 4788 N

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What is the function of the mitochondria?
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If the absolute pressure of a gas is 550.280 kPa, its gage pressure is
aivan3 [116]

By definition we have to:

Pabs = Patm + Pg

Where,

Pabs: absolute pressure

Patm: atmospheric pressure

Pg: gage pressure

The atmospheric pressure is constant and its value is:

Patm = 101.325 kPa

Then, by clearing gage pressure we have:

Pg = Pabs - Patm

Substituting values we have:

Pg = 550.280 - 101.325\\Pg = 448.955 KPa

Answer:

If the absolute pressure of a gas is 550.280 kPa, its gage pressure is:

D. 448.955 kPa

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Answer:

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