Given:
Area of pool = 3m×4m
Diameter of orifice = 0.076m
Outlet Velocity = 6.3m/s
Accumulation velocity = 1.5cm/min
Required:
Inlet flowrate
Solution:
The problem can be solved by this general formula.
Accumulation = Inlet flowrate - Outlet flowrate
Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice
First, we need to convert the units of the accumulation velocity into m/s to be consistent.
Accumulation velocity = 1.5cm/min × (1min/60s)×(1m/100cm)
Accumulation velocity = 0.00025 m/s
We then calculate the area of the pool and the area of the orifice by:
Area of pool = 3 × 4 m²
Area of pool = 12m²
Area of orifice = πd²/4 = π(0.076m)²/4
Area of orifice = 0.00454m²
Since we have all we need, we plug in the values to the general equation earlier
Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice
0.00025 m/s × 12m² = Inlet flowrate - 6.3m/s × 0.00454m²
Transposing terms,
Inlet flowrate = 0.316 m³/s
Answer: For ideal machine efficiency = 1. Hence M.A = V. R. The V. R of an ideal machine and the practical machine is a constant or is the same for both
The limits which would be age appropriate for toddlers include being flexible and realistic while that of a teen should be more rigid.
<h3>Who are Toddlers?</h3>
This refers to a child whose age ranges from 1 year to 4 years and limits set for them should be flexible due to it helping them feel more secure and decreases anxiety.
Example of limits that you may have for a teen is reducing their screen time while an example of limits for toddlers is correcting their junk eating habits. Teens should have a rigid limit so as to enable them do the right things at all times due to their strong emotions.
Read more about Limits here brainly.com/question/1419949
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<h2>Olivia is on a Swing at Playground - Option 2 </h2>
Olivia is on a swing at the playground. Her kinetic energy increasing at x and her potential energy decreasing at x. At mean position velocity is maximum so kinetic energy ( K.E ) is also maximum and at mean position potential energy is minimum. Therefore, kinetic energy is increasing and potential energy decreasing at x.
