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3 years ago

What part of the water is affected by a wave in deep water

Physics

1 answer:

krok68 [10]3 years ago

5 0

Wave base is the most affected by a wave in deep water. :]

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A car travels 90 meters due north in 15 seconds. Then the car

tatyana61 [14]

I got you kid It’s A- 2.5m/sb

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2 years ago

As you may well know, placing metal objects inside a microwave oven can generate sparks. Two of your friends are arguing over th

Fofino [41]

Answer:

$5.04\cdot 10^8 A$

Explanation:

The work function of the metal corresponds to the minimum energy needed to extract a photoelectron from the metal. In this case, it is:

$\phi = 3.950\cdot 10^{-19}J$

So, the energy of the incoming photon hitting on the metal must be at least equal to this value.

The energy of a photon is given by

$E=\frac{hc}{\lambda}$

where

h is the Planck's constant

c is the speed of light

$\lambda$ is the wavelength of the photon

Using $E=\phi$ and solving for $\lambda$ , we find the maximum wavelength of the radiation that will eject electrons from the metal:

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{3.950\cdot 10^{-19} J}=5.04\cdot 10^{-7}m$

And since

1 angstrom = $10^{-15}m$

The wavelength in angstroms is

$\lambda=\frac{5.04\cdot 10^{-7} m}{10^{-15} m/A}=5.04\cdot 10^8 A$

3 0

3 years ago

Which of the following best describes the function of a plant's flowers?

noname [10]

Answer: The function of a plant's flower is reproduce. Since the flowers are the reproductive organs of plant, they mediate the joining of the sperm, contained within pollen, to the ovules contained in the ovary.

Explanation:

8 0

2 years ago

A player holds two baseballs a height h above the ground. He throws one ball vertically upward at speed v0 and the other vertica

Degger [83]

Answer:

a) v = √(v₀² + 2g h), b) Δt = 2 v₀ / g

Explanation:

For this exercise we will use the mathematical expressions, where the directional towards at is considered positive.

The velocity of each ball is

ball 1. thrown upwards vo is positive

v² = v₀² - 2 g (y-y₀)

in this case the height y is zero and the height i = h

v = √(v₀² + 2g h)

ball 2 thrown down, in this case vo is negative

v = √(v₀² + 2g h)

The times to get to the ground

ball 1

v = v₀ - g t₁

t₁ = $\frac{v_{o} - v }{ g}$

ball 2

v = -v₀ - g t₂

t₂ = - \frac{v_{o} + v }{ g}

From the previous part, we saw that the speeds of the two balls are the same when reaching the ground, so the time difference is

Δt = t₂ -t₁

Δt = $\frac{1}{g} \ [(v_{o} - v) - ( - v_{o} - v) ]$

Δt = 2 v₀ / g

6 0

2 years ago

On Mars, where air resistance is negligible, an astronaut drops a rock from a cliff and notes that the rock falls about d meters

dimulka [17.4K]

Answer:

$d_1 = 16 d$

Explanation:

As we know that initial speed of the fall of the stone is ZERO

$v_i = 0$

also the acceleration due to gravity on Mars is g

so we have

$d = v_i t + \frac{1}{2}gt^2$

now we have

$d = 0 + \frac{1}{2}g t^2$

now if the same is dropped for 4t seconds of time

then again we will use above equation

$d_1 = 0 + \frac{1}{2}g(4t)^2$

$d_1 = 16(\frac{1}{2}gt^2)$

$d_1 = 16 d$

7 0

3 years ago

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