Is it possible for a tennis ball to have more momentum than a cannonball? explain

When a ball is launched from the ground at a 45° angle to the horizontal, it falls back to the ground 50 m from the launch point

Inessa [10]

Answer:

Explanation:

Given

angle through which ball is launched $=45^{\circ}$

Range of ball=50 m

Range of projectile is $=\frac{u^2sin2\theta }{g}$

$50=\frac{u^2sin90}{9.8}$

u=22.136 m/s

If ball is thrown straight upward

$v^2-u^2=2as$

$0-(22.136)^2=2(-9.8)s$

$s=\frac{22.136^2}{2\times 9.8}$

s=25 m

(b)For Projectile time of flight is

$t=\frac{2usin\theta }{g}$

$t=\frac{2\times 22.136\times sin45}{9.8}$

t=3.19 s

7 0

2 years ago

A car traveling 34 mi/h accelerates uniformly for 4 s, covering 615 ft in this time. What was its acceleration? Round your answe

Contact [7]

Answer:

51.94 ft/s²

257.63 ft/s

Explanation:

t = Time taken = 4 s

u = Initial velocity = 34 mi/h

v = Final velocity

s = Displacement = 615 ft

a = Acceleration

Converting velocity to ft/s

$34\ mi/h=\frac{34\times 5280}{3600}=49.87\ ft/s$

Equation of motion

$s=ut+\frac{1}{2}at^2\\\Rightarrow a=2\frac{s-ut}{t^2}\\\Rightarrow a=2\left(\frac{615-49.87\times 4}{4^2}\right)\\\Rightarrow a=51.94\ ft/s^2$

Acceleration is 51.94 ft/s²

$v=u+at\\\Rightarrow v=49.87+51.94\times 4\\\Rightarrow v=257.63\ ft/s$

Final velocity at this time is 257.63 ft/s

5 0

3 years ago

(b) The particle displacement y of air molecules due to a sound wave is given by y 4m and w = = 0.008 cos wt sin kz. Where k - m

serious [3.7K]

The distance between two consecutive nodes and the amplitude after 0.56s are m/2 and 1.75×10^(-4) m respectively.

<h3>What's the distance between consecutive nodes of the displacement of air molecules?</h3>

Wavelength is the distance between two consecutive nodes or toughs or crests or anti-nodes.
So, distance between consecutive nodes = wavelength = 2π÷k

= 2π/(4π÷m)

= m/2

<h3>What's the amplitude after 0.56s of the displacement of air molecules?</h3>

Displacement after 0.56 s = 0.008×cos(50π×0.56s)

=1.75×10^(-4) m

Thus, we can conclude that the distance between consecutive nodes and displacement after 0.56 s are m/2 and 1.75×10^(-4) m respectively.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: The particle displacement y of air molecules due to a sound wave is given by y=0.008coswtsinkz where k=4π÷m and w=50π rads/s.

Calculate:

I) the distance between 2 consecutive nodes

ii) the amplitude after 0.565s

Learn more about the wavelength here:

brainly.com/question/10750459

#SPJ1

8 0

1 year ago

In regions where few species existed before or where species were wiped out what occurs?

marysya [2.9K]

I cant really say but i believe it is called extinction

5 0

3 years ago

Calculate two stars appear to you to have the same brightness. if star a is 7.00 light-years away from you, while star b is 15.0

vagabundo [1.1K]

It is eight times more than the star A.

<h3>What is luminosity and on which it depends?</h3>

The luminosity of an object is a measure of its intrinsic brightness and is defined as the amount of energy the object emits in a fixed time.

luminousity depends upon the two factors are:

1) The star's actual brightness

Some stars are naturally more luminous than others ,so the brightness level from one star to next star is significantly different.

2) The star distance from us

The more distance of an object the dimmer it appears.

Energy emitted = sAT⁴

where s is stefan constant

A is surface area and T is temperature .

to learn more about Luminosity click here brainly.com/question/14140223

#SPJ4

7 0

11 months ago

Is it possible for a tennis ball to have more momentum than a cannonball? explain ​

Is it possible for a tennis ball to have more momentum than a cannonball? explain