Answer:
S(6, 10)
Step-by-step explanation:
1. The Midpoint (in this case, M) will always be halfway between both R and S (or other characters in some cases).
2. As M is only one X value away from R, it is only 1 X value from S as well, but in the other direction.
3. (7, 10) - (1, 0) = (6, 10)
The (7, 10) is the Midpoint Coordinates.
The (1, 0) is the distance from M to R.
The (6, 10) is the coordinates of S.
Answer:
229?
Step-by-step explanation:
Answer:
Length of the rectangle = 16 inches
Width of the rectangle = 12 inches
Step-by-step explanation:
Let the length of the rectangle be represented by x.
Then width can be expressed as ![\[\frac{x}{2}+4\] ](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bx%7D%7B2%7D%2B4%5C%5D%0A)
Perimeter of a rectangle is the sum of four sides of the rectangle.
This can be expressed as 2*(length + breadth)
= ![\[2* (x + \frac{x}{2}+4)\]](https://tex.z-dn.net/?f=%5C%5B2%2A%20%28x%20%2B%20%5Cfrac%7Bx%7D%7B2%7D%2B4%29%5C%5D)
= ![\[2* (\frac{3x}{2}+4)\]](https://tex.z-dn.net/?f=%5C%5B2%2A%20%28%5Cfrac%7B3x%7D%7B2%7D%2B4%29%5C%5D)
= ![\[3x + 8\]](https://tex.z-dn.net/?f=%5C%5B3x%20%2B%208%5C%5D)
But perimeter is given as 56.
So, ![\[3x + 8 = 56\] ](https://tex.z-dn.net/?f=%5C%5B3x%20%2B%208%20%3D%2056%5C%5D%0A)
=> ![\[3x = 48\]](https://tex.z-dn.net/?f=%5C%5B3x%20%3D%2048%5C%5D)
=> ![\[x = 16\]](https://tex.z-dn.net/?f=%5C%5Bx%20%3D%2016%5C%5D)
Hence length of the rectangle = 16 inches
Width of the rectangle =
= 12 inches
$338 / 2 = $169
A = a^2 = 169
a= 13
answer
13ft
Answer:
12.9 yd
Step-by-step explanation:
It helps if you draw a triangle. Draw a horizontal segment. That is the ground. Now at the left end start a new segment that goes up to the right at approximately 15 degrees until it its other endpoint directly above the right endpoint of the horizontal segment. Connect these two endpoints. The vertical side on the right shows the height of the kite. The hypotenuse is the string.
For the 15-deg angle, the height of the triangle is the opposite leg, and the string is the hypotenuse. The trig ratio that relates the opposite leg tot he hypotenuse is the sine.




