<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B3%7Dx%20%2B%2025%20%3D%2033" id="TexFormula1" title=" \frac{4}{3}x + 25 =

All categories

monitta

3 years ago

33" alt=" \frac{4}{3}x + 25 = 33" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

sattari [20]3 years ago

7 0

$\frac{4}{3}x = 33 - 25$
$\frac{4}{3}x = 8$
$x = 8 \div \frac{4}{3}$
$x = 6$

You might be interested in

Given the quadratic function g(x)=(x-2)^2+3, state the vertex of g(x)

Nonamiya [84]

The answer would be (2,3)

7 0

3 years ago

A letter used to represent a number in equations or expressions

natita [175]

The answer is “x”. “x” represents the missing number in the problem.

Example:
16+x=20
The missing number, 4, would be represented as x. Hope this helps!

6 0

3 years ago

What is the value of x? How do you set up to solve?

nlexa [21]

Answer:

3x-22=80+x

3x-x=80+22

2x=102

x=51

Step-by-step explanation:

the exterior angle is (3x-22) and then is equal to sum of 80 and x

and then we get 51

6 0

3 years ago

Read 2 more answers

A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use of one particular cust

Fiesta28 [93]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given set of values

$321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320$

STEP 2: Write the formula for calculating the Standard deviation of a set of numbers

$\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ where\text{ }x_i\text{ are data points,} \\ \bar{x}\text{ is the mean} \\ \text{n is the number of values in the data set} \end{gathered}$

STEP 3: Calculate the mean

$\begin{gathered} \bar{x}=\frac{\sum ^{}_{}x_i}{n} \\ \bar{x}=\frac{\sum ^{}_{}(321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320)}{20} \\ \bar{x}=\frac{8453}{20}=422.65 \end{gathered}$

STEP 4: Calculate the Standard deviation

$\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ \sum ^{}_{}(x_i-\bar{x})^2\Rightarrow\text{Sum of squares of differences} \\ \Rightarrow10332.7225+657.9225+18591.3225+982.8225+2740.52251+9731.8225+3522.4225+18319.6225+2878.3225 \\ +8163.1225+1417.5225+3925.0225+1321.3225+386.1225+5677.6225+2953.9225+3800.7225 \\ +3209.2225+2565.4225+10537.0225 \\ \text{Sum}\Rightarrow108974.0275 \\ \\ S\tan dard\text{ deviation}=\sqrt[]{\frac{111714.55}{20-1}}=\sqrt[]{\frac{111714.55}{19}} \\ \Rightarrow\sqrt[]{5879.713158}=76.67928767 \\ \\ S\tan dard\text{ deviation}\approx76.68 \end{gathered}$

Hence, the standard deviation of the given set of numbers is approximately 76.68 to 2 decimal places.

STEP 5: Calculate the First and third quartile

$\begin{gathered} \text{IQR}=Q_3-Q_1 \\ \\ To\text{ get }Q_1 \\ We\text{ first arrange the data in ascending order} \\ \mathrm{Arrange\: the\: terms\: in\: ascending\: order} \\ 320,\: 321,\: 324,\: 360,\: 361,\: 366,\: 369,\: 372,\: 385,\: 397,\: 403,\: 454,\: 459,\: 475,\: 477,\: 482,\: 498,\: 513,\: 558,\: 559 \\ Q_1=(\frac{n+1}{4})th \\ Q_1=(\frac{20+1}{4})th=\frac{21}{4}th=5.25th\Rightarrow\frac{361+366}{2}=\frac{727}{2}=363.5 \\ \\ To\text{ get }Q_3 \\ Q_3=(\frac{3(n+1)}{4})th=\frac{3\times21}{4}=\frac{63}{4}=15.75th\Rightarrow\frac{477+482}{2}=\frac{959}{2}=479.5 \end{gathered}$

STEP 6: Find the Interquartile Range

$\begin{gathered} IQR=Q_3-Q_1 \\ \text{IQR}=479.5-363.5 \\ \text{IQR}=116 \end{gathered}$

Hence, the interquartile range of the data is 116

3 0

1 year ago

Identify the sets of lines to which the given line is a transversal. Line m

Alekssandra [29.7K]

Answer:

Only J and I

Step-by-step explanation:

Transversal Lines are only transversal to sets of parallel lines in which they pass through and P is not parallel to any.

8 0

3 years ago