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Kobotan [32]
3 years ago
11

PLEASE HELP ! Trying to make honor roll !

Mathematics
2 answers:
Aleks04 [339]3 years ago
8 0

Answer:

Point C

Step-by-step explanation:

When you graph the two equations, they meet at point c, which is the solution

nadezda [96]3 years ago
3 0

Answer:

Point C

Step-by-step explanation:

You know the x so you can substitute that into the point:

(4, y)

You don't know y but you can substitute in the x and solve the equation. You would get -3. So the point would be:

(4, -3)

Find that point on the graph and it's Point C.

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The temperature was 19 degrees Fahrenheit on Monday and 31 degrees Fahrenheit on Tuesday. How much did the temperature rise?
Lera25 [3.4K]

Answer:

31-19=12°F

12°F

Step-by-step explanation

If it was 19 degrees on Monday and 31 degrees on Tuesday you have to see how much did it go up in temp. So..

the difference between 19 and 31 is 12, so that means it went up by 12°F.

7 0
3 years ago
0.8342 as a fraction?
ratelena [41]

Answer:

4171/5000

Step-by-step explanation:

When diving 4171 by 5000, you get the answer of 0.8342. If you are using a calculator, you can use a button that allows you to convert decimals to fractions and vice versa.

5 0
3 years ago
Question 19 Only, Please show your work.<br><br> Solve the problem.
ankoles [38]

Answer:

5\sqrt{2}

Step-by-step explanation:

Draw a diagonal (line segment from one corner to the opposite corner).  You'll form two right triangles with the diagonal being the hypotenuse of both triangles.

Use the Pythagorean Theorem:  (leg)^2 + (leg)^2 = (hypotenuse)^2.

Let  h  represent the length of the hypotenuse.

h^2 = 5^2+5^2\\h^2=25 + 25\\h^2 =50\\h=\sqrt{50}\\h=5\sqrt{2}

The question is just a bit vague. It should say opposite corners.  I'm assuming the question does not mean the length of one side!

5 0
2 years ago
Here's my last question
N76 [4]

Answer:

19.14lb

Step-by-step explanation:


3 0
3 years ago
What is the exact number of 2000
GaryK [48]
If you are rounding it will be the same thing
5 0
3 years ago
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