Mark tossed six balls while playing a number game. Three balls landed in one section, and three balls landed in another section.
1 answer:
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Answer:
Probability that the sample contains at least five Roman Catholics = 0.995 .
Step-by-step explanation:
We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.
The Binomial distribution probability is given by;
P(X = r) = for x = 0,1,2,3,.......
Here, n = number of trials which is 8 in our case
r = no. of success which is at least 5 in our case
p = probability of success which is probability of Roman Catholic of
0.90 in our case
So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)
=
= 56 * + 28 *
+ 8 *
+ 1 *
= 0.995
Therefore, probability that the sample contains at least five Roman Catholics is 0.995.
Answer:
look below
Step-by-step explanation:
y = 2 (x + 3)^2 - 2
Geometric figure: parabola
Alternate forms:
y = 2 (x + 2) (x + 4)
y = 2 (x^2 + 6 x + 8)
-2 x^2 - 12 x + y - 16 = 0
Expanded form:
y = 2 x^2 + 12 x + 16
Roots:
x = -4
x = -2
<u>Properties as a real function: </u>
Domain - R (all real numbers)
Range - {y element R : y>=-2}
Partial derivatives:
d/dx(2 (x + 3)^2 - 2) = 4 (x + 3)
d/dy(2 (x + 3)^2 - 2) = 0
Implicit derivatives:
(dx(y))/(dy) = 1/(12 + 4 x)
(dy(x))/(dx) = 4 (3 + x)
Global minimum:
min{2 (x + 3)^2 - 2} = -2 at x = -3
