All categories

3 years ago

Least to greatest 2/3, -2 2/5, 0.5, -0.8

Mathematics

1 answer:

baherus [9]3 years ago

3 0

Answer:

-2 2/5, -0.8, 0.5, 2/3

Step-by-step explanation:

We have four values, two that are fractions and two that are decimals and are asked to put them from least to greatest.

We have a dillema of values in this question, two are fractions and two are decimals. We need to convert all of them towards one symbol to get our answer.

Let's try decimals, since they are more easier to see which is the bigger value.

Start with 2/3, what is 2 divided by 3?

2/3

0.6 repeated.

As of now, we have 0.6 repeated, -2 2/5, 0.5, and -0.8.

Now do the second fraction, turn -2 2/5 to an improper fraction by multiplying the whole number by the denominator and adding the numerator.

-2 * 5 + 2

-10 + 2

-8/5

Now convert -8/5 to a decimal :

-8/5

-1.6

Now we have all decimals, put the from least to greatest.

0.6 repeated, -1.6, 0.5, -0.8

-1.6, -0.8, 0.5, 0.6 repeated

Therefore our list from least to greatest is :

-2 2/5, -0.8, 0.5, 2/3

You might be interested in

Which expression is equivalent to the given expression? Assume the denominator does not equal zero.

bulgar [2K]

D
For these type of problems download photo math
It’ll be faster than here with steps!

8 0

2 years ago

Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant

son4ous [18]

The chain rule states that

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

Since $\ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2)$ , you have

$\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}$

and

$\dfrac{\mathrm dx}{\mathrm dt}=\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t$

Also, since $x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t$ , the derivative is

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\tan t$

4 0

2 years ago

PLZ help asap i need to help finish this

Levart [38]

Answer:

ok i will

Step-by-step explanation:

pls give me a little bit of time ok

5 0

2 years ago

Kinda need some help:)

Natali [406]

1.
f(x) = x
g(x) = x + 3

For each x value you use in f(x) and g(x), the corresponding y value in g(x) is always 3 more than in f(x). If each y-coordinate is 3 more, that means the graph is shifted 3 units up. The graph of f(x) is shifted 3 units up to create the graph of g(x).

2.
The first term is -0.5.
Then each term goes up by 0.25.

1st term: -0.5
2nd term: -0.5 + 0.25 = -0.5 + 0.25(1)
3rd term: -0.5 + 0.25 + 0.25 = -0.5 + 0.25(2)
4th term: -0.5 + 0.25 + 0.25 + 0.25 = -0.5 + 0.25(3)
nth term: -0.5 + 0.25(n - 1)

-0.5 + 0.25(n - 1) = -0.5 + 0.25n - 0.25 = -0.75 + 0.25n = 0.25n - 0.75

Answer is C.

5 0

3 years ago

Tell if the ordered pair is a solution of the system of inequalities.

ale4655 [162]

Answer:

top one yes, bottom one no

Step-by-step explanation:

3 0

3 years ago