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maxonik [38]
3 years ago
14

(1/4)^(2m)=64^m Help please

Mathematics
1 answer:
Marrrta [24]3 years ago
8 0

Answer:

I think the answer is m = 0

Step-by-step explanation:

2^(-4m) = 2^(6m)   set the exponent equal

- 4m = 6m   Move variable to the left

- 4m- 6m = 0   collect like terms

- 10m = 0   Divide both sides by - 10

m = 0

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Consider the initial value function y given by
Nuetrik [128]

Answer:

y(s) = \frac{5s-53}{s^{2} - 10s  + 26}

we will compare the denominator to the form (s-a)^{2} +\beta ^{2}

s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}

comparing coefficients of terms in s

s^{2} : 1

s: -2a = -10

      a = -2/-10

      a = 1/5

constant: a^{2}+\beta ^{2} = 26

               (\frac{1}{5} )^{2} + \beta ^{2} = 26\\\\\beta^{2} = 26 - \frac{1}{10} \\\\\beta =\sqrt{26 - \frac{1}{10}} =5.09

hence the first answers are:

a = 1/5 = 0.2

β = 5.09

Given that y(s) = A(s-a)+B((s-a)^{2} +\beta ^{2} )

we insert the values of a and β

  \\5s-53 = A(s-0.2)+B((s-0.2)^{2} + 5.09^{2} )

to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A

5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)

-52 = B(26)

B = -52/26 = -2

to get A lets substitute s=0.4

5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)

-51 = 0.2A - 52.08

0.2A = -51 + 52.08

A = -1.08/0.2 = 5.4

<em>the constants are</em>

<em>a = 0.2</em>

<em>β = 5.09</em>

<em>A  = 5.4</em>

<em>B = -2</em>

<em></em>

Step-by-step explanation:

  1. since the denominator has a complex root we compare with the standard form s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}
  2. Expand and compare coefficients to obtain the values of a and <em>β </em>as shown above
  3. substitute the values gotten into the function
  4. Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
  5. after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above

Thanks...

3 0
3 years ago
Please help me with this question i need the answer asap
Nataly [62]

D) Function A is non-linear and Function B is linear.

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3 years ago
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Use one transformation to solve n-4.6=2.98
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What are the options of tranformation ??/
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3044 in a base 5 to a base 10
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3,059 I don’t really care
4 0
2 years ago
Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the accou
storchak [24]

Hello!

Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the account and does not withdraw any money. What is the balance of Lynne's account in 5years

Data:

P = 35000

r = 4% = 0,04

n = 4

t = 5

P' = ?

I = ?  

We have the following compound interest formula

P' = P*(1+\dfrac{r}{n})^{nt}

P' = 35000*(1+\frac{0,04}{4})^{4*5}

P' = 35000*(1+0,01)^{20}

P' = 35000*(1,01)^{20}

P' = 35000*(1.22019003995...)

P' \approx 42,706.66

So the new principal P' after 5 years is approximately $42,706.66.  

Subtracting the original principal from this amount gives the amount of interest received:

P' - P = I

42,706.66 - 35000 = \boxed{\boxed{7,706.66}}\end{array}}\qquad\checkmark

________________________

I Hope this helps, greetings ... Dexteright02! =)

4 0
3 years ago
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