The account balance after 3 years if the interest is compounded continuously is $5,142.62
<h3>How to find compound interest?</h3>
- Principal, P = $4,700
- Time,t = 3 years
- Interest rate, r = 3%
r = 3/100
r = 0.03 rate per year,
A = Pe^rt
A = 4,700.00(2.71828)^(0.03)(3)
= 12,775.916^0.09
A = $5,142.62
Therefore, the account balance after 3 years if the interest is compounded continuously is $5,142.62
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Answer:
$38.46
Step-by-step explanation:
Minimum payment = 15% of balance
Balance = $256.38
Therefore
15% of $256.38
Change 15% to decimal
15% /100% x $256.38
0.15 x $256.38
$38.46
Her minimum payment is $38.46
#3) 9/3= 3
90/3=30
900/3=300
9.000/3=3.3000
#4)1/2, 2/3, 2/5, 3/4
Answer:
![\dfrac{-15}{8}](https://tex.z-dn.net/?f=%5Cdfrac%7B-15%7D%7B8%7D)
Step-by-step explanation:
<h3>Fraction division:</h3>
![\sf \dfrac{3}{4} \ \div \dfrac{-2}{5}](https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B3%7D%7B4%7D%20%5C%20%5Cdiv%20%5Cdfrac%7B-2%7D%7B5%7D)
Use KCF method.
- Keep the first fraction.
- Change division to multiplication
- Flip the second fraction.
![\sf \dfrac{3}{4} \ \div \dfrac{-2}{5}=\dfrac{3}{4}*\dfrac{-5}{2}](https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B3%7D%7B4%7D%20%5C%20%5Cdiv%20%5Cdfrac%7B-2%7D%7B5%7D%3D%5Cdfrac%7B3%7D%7B4%7D%2A%5Cdfrac%7B-5%7D%7B2%7D)
![\sf = \dfrac{3*(-5)}{4*2}\\\\ =\dfrac{-15}{8}](https://tex.z-dn.net/?f=%5Csf%20%3D%20%5Cdfrac%7B3%2A%28-5%29%7D%7B4%2A2%7D%5C%5C%5C%5C%20%3D%5Cdfrac%7B-15%7D%7B8%7D)