Answer:
speed = 10.1215 m/s
Explanation:
speed = distance / time
speed = 100 / 9.88 = 10.1215 m/s
Heya!!
For calculate period, lets applicate formula:
![\boxed{T=1/f}](https://tex.z-dn.net/?f=%5Cboxed%7BT%3D1%2Ff%7D)
<u>Δ Being Δ</u>
T = Period = ?
f = Frequency = 660 Hz
⇒ Let's replace according the formula:
![\boxed{T=1/660\ Hz }](https://tex.z-dn.net/?f=%5Cboxed%7BT%3D1%2F660%5C%20Hz%20%7D)
⇒ Resolving
![\boxed{T=0,0015\ s}](https://tex.z-dn.net/?f=%5Cboxed%7BT%3D0%2C0015%5C%20s%7D)
Result:
The period of that wave is <u>0,0015 seconds.</u>
<u>Δ IMPORTANT Δ</u>
The period is the INVERSE of the frequency. (T = 1 / f).
And the frequency is the inverse of the period (f = 1 / T)
Good Luck!!
Yeah You are doing it correct
The relationship between resistance R and resistivity
![\rho](https://tex.z-dn.net/?f=%5Crho)
is
![R= \frac{\rho L}{A}](https://tex.z-dn.net/?f=R%3D%20%5Cfrac%7B%5Crho%20L%7D%7BA%7D%20)
(1)
where L is the length of the wire and A is the cross-sectional area.
In our problem, the radius of the wire is half the diameter: r=1 mm=0.001 m, so the cross-sectional area is
![A=\pi r^2 = \pi (0.001 m)^2=3.14 \cdot 10^{-6} m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%20%3D%20%5Cpi%20%280.001%20m%29%5E2%3D3.14%20%5Ccdot%2010%5E%7B-6%7D%20m%5E2)
The length of the wire is L=20 m and the resistance is
![R=0.25 \Omega](https://tex.z-dn.net/?f=R%3D0.25%20%5COmega)
.
By re-arranging equation (1), we can find the resistivity of the wire:
Answer:
the spring coefficient is
k=16N/m
Explanation:
Hooks law states that provided the elasticity of a material is not exceeded the extension e is proportional to the applied force
Step one
Analysis of the problem
From analysis of the problem
The mass has a potential energy due to the height it was dropped from, the potential energy is then stored in the spring since it was dropped on the spring which compresses it by 0.5m
Step two
Data
Mass of object m=0.2kg
Height of building =10m
Compression of spring e=0.5m
Spring constant k=?
Step three
According to the principle of energy conservation
mgh=1/2(k*e^2)
Making k subject of formula we have
k=2mgh/e^2
Substituting our data into the expression to get k
Assuming g=9.81m/s
k=2*0.2*10/0.5^2
k=4/0.25
k=16N/m