Which of the following statements about nuclear power is true?

Which of the following is a way that science and the economy interact

Artist 52 [7]

Answer:

You didn't add the choices but I'll add some ideas anyway.

Explanation:

Let's start with perhaps the most obvious impact of science on the economy: technology. Scientific discoveries lead to the development of new technologies, which then enter into international markets as highly desirable products.

While humans have always traded technologies, the relationship between technological development and economic growth really dates back to the Industrial Revolution of the 18th and 19th centuries. This was the first time that products were being produced on a massive scale, and it was new technologies in steam engines that allowed this to happen.

As people produced more goods, they developed more complex networks of economic exchange across the world. In fact, our modern ideas about free-market economies and capitalism actually date back to this same time period.

Our modern technologies and our modern economies developed simultaneously. We couldn't have one without the other. Today the United States' economy is very largely dependent on the exportation of communications and digital technologies. Its place in the global economy is not defined by its agriculture or raw products, but by its technologies.

8 0

3 years ago

study a 75kg person stands on a scale in an elevator what does read in n and in kg when the elevator is at rest?

Verdich [7]

To solve this problem we will use Newton's second law in order to obtain the weight of a person. The second law tells us that

F = ma

Where,

m = mass

a = Acceleration

In this particular case, the acceleration is equal to that exerted by the earth through gravitational acceleration, so if the person's weight is 75Kg and the gravity is $9.8m / s^2$ , the weight of the body will be,

$F_W =mg$

$F_W = (75kg)(9.8m/s^2 )$

$F_W = 735.75N$

When the elevator is at rest this reads 735.75N and 75Kg (The same mass of the person)

6 0

3 years ago

The components of vector Ã are:

Nookie1986 [14]

Answer:

|A| = √(Ax)^2 + (Ay)^2

|A| = √(7.6)^2 + (-6.4)^2

|A| = √98.72

|A| = 9.9

6 0

3 years ago

Read 2 more answers

Based on what you have learned about gravity, mass, and distance, write one paragraph to answer the following questions.

natka813 [3]

Bigger objects have more gravitational pull. Bigger, meaning the size and mass. The closer you are to the object, the stronger the pull is. The earth is much bigger, and has a bigger mass than the moon, meaning that the moon is able to orbit around the earth. You are closer to the earth, so you dont randomly get pulled towards thw moon, because earts gravitational pull is stronger than the moons.

7 0

3 years ago

To measure the coefficient of kinetic friction by sliding a block down an inclined plane the block must be in equilibrium.

lozanna [386]

Answer:

a)

Explanation:

A block sliding down an inclined plane, is subject to two external forces along the slide.
One is the component of gravity (the weight) parallel to the incline.
If the inclined plane makes an angle θ with the horizontal, this component (projection of the downward gravity along the incline, can be written as follows:

$F_{gp} = m*g* sin \theta (1)$

(taking as positive the direction of the movement of the block)

The other force, is the friction force, that adopts any value needed to meet the Newton's 2nd Law.
When θ is so large, than the block moves downward along the incline, the friction force can be expressed as follows:

$F_{f} = \mu_{k} * N (2)$

The normal force, adopts the value needed to prevent any vertical movement through the surface of the incline:

$N = m*g* cos \theta (3)$

In equilibrium, both forces, as defined in (1), (2) and (3) must be equal in magnitude, as follows:

$m*g* sin \theta = \mu_{k} * m*g* cos \theta$

As the block is moving, if the net force is 0, according to Newton's 2nd Law, the block must be moving at constant speed.
In this condition, the friction coefficient is the kinetic one (μk), which can be calculated as follows:

$\mu_{k} = tg \theta$

8 0

3 years ago