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3 years ago

Compounds formed from the attraction of oppositely charged ions are called

Physics

1 answer:

Readme [11.4K]3 years ago

8 0

Answer:

Ionic bond

Explanation:

Also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound.

Hope this helps! brainliest welcomed! :)

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Standing at the same location, which organism would have the GREATEST gravitational attraction to the earth?

Nastasia [14]

To claculate the gravitational attraction between two bodies with mass 1(m1) and mass 2 (m2) you need to use the equation:

F= G ((m1*m2)/r^2)

Where;
G is the gravitational constant (6.67E-11 m^3 s-2 Kg-1) and
r is the distance between the two objects.

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3 years ago

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A spring that has a force constant of 1050 N/m is mounted vertically on the ground. A block of mass 1.95 kg is dropped from rest

aleksandrvk [35]

Answer:

25.2 cm

Explanation:

K = 1050 N/m

m = 1.95 kg

h = 1.75 m

By the conservation of energy, the potential energy of the block is converted into the potential energy stored in the spring

m g h = 1/2 x k x y^2

Where, y be the distance by which the spring is compressed.

1.95 x 9.8 x 1.75 = 1/2 x 1050 x y^2

33.44 = 525 x y^2

y = 0.252 m

y = 25.2 cm

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3 years ago

Action and reaction forces are described by which of Newton's laws of motion?

Ilia_Sergeevich [38]

Answer:

The first one

Explanation:

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4 years ago

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A satellite orbiting the earth is directly over a point on the equator at 12:00 midnight every four days. It is not over that po

Mrrafil [7]

Answer:

106417026.88435 m

Explanation:

T = Time period of the satellite = 4 days

m = Mass of the Earth = 5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Time period is given by

$T=2\pi\sqrt{\dfrac{r^3}{GM}}\\\Rightarrow r=\left(\dfrac{T^2GM}{4\pi ^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=\left(\dfrac{(4\times 24\times 60\times 60)^2\times 6.67\times 10^{-11}\times 5.972\times 10^{24}}{4\pi ^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=106417026.88435\ m$

The radius of the satellite's orbit is 106417026.88435 m

5 0

3 years ago

Force f⃗ =−10j^n is exerted on a particle at r⃗ =(7i^+5j^)m. part a what is the torque on the particle about the origin?

cluponka [151]

Answer:

Torque, $\tau=0i+0j-70k$

Explanation:

It is given that,

Force acting on the particle, $F=-10j\ N$

Position of the particle, $r=(7i+5j)\ m$

We need to find the torque on the particle about the origin. It is equal to the cross product of position and the force. Its formula is given by :

$\tau=r\times F$

$\tau=(7i+5j)\times (-10j)$

The cross product of vectors is given by :

$\tau=\begin{pmatrix}0&0&-70\end{pmatrix}$

$\tau=0i+0j-70k$

So, the torque on the particle about the origin $0i+0j-70k$ . Hence, this is the required solution.

6 0

3 years ago