Athlete meseret defar runs at 10m<br>

A trailer mechanic pushes a 2500 kg car, home to a speed v, performing a job during the 5000 J. In this process, the car moves 2

gregori [183]

Hope it's visible. All the best :-D

6 0

3 years ago

As a stunt for movie two cars are to collide with each other head on. The two cars are initially 125 apart. Car A is heading str

Tema [17]

Answer:

3.39724 seconds

23.0824792352 m, 101.917520765 m

13.58896 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

The equation of motion will be

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow 125=30\times t+\dfrac{1}{2}\times 4\times t^2\\\Rightarrow 2t^2+30t-125=0\ m$

$t=\frac{5\left(\sqrt{19}-3\right)}{2},\:t=-\frac{5\left(3+\sqrt{19}\right)}{2}\\\Rightarrow t=3.39724, -18.39724$

The time at which the cars collide is 3.39724 seconds

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 4\times 3.39724^2\\\Rightarrow s=23.0824792352\ m$

Car B traveled 23.0824792352 m and Car A traveled 125-23.0824792352 = 101.917520765 m

$v=u+at\\\Rightarrow v=0+4\times 3.39724\\\Rightarrow v=13.58896\ m/s$

The speed of car B is 13.58896 m/s

4 0

3 years ago

How would the force of gravity between two objects change if the mass of

belka [17]

Answer:

Option C. The force between them would be 4 times larger than with the

initial masses.

Explanation:

To know which option is correct, we shall determine the force of attraction between the two masses when their masses are doubled. This can be obtained as follow:

From:

F = GMₐM₆/ r²

Keeping G/r² constant, we have

F₁ = MₐM₆

Let the initial mass of both objects to be m

F₁ = MₐM₆

F₁ = m × m

F₁ = m²

Next, let the masses of both objects doubles i.e 2m

F₂ = MₐM₆

F₂ = 2m × 2m

F₂ = 4m²

Compare the initial and final force

Initial force (F₁) = m²

Final (F₂) = 4m²

F₂ / F₁ = 4m² / m²

F₂ / F₁ = 4

F₂ = 4F₁ = 4m²

From the above illustrations, we can see that when the mass of both objects doubles, the force between them would be 4 times larger than with the

initial masses.

Thus, option C gives the correct answer to the question.

5 0

3 years ago

Sayuri is a new, eight-year-old Japanese girl in the neighborhood. When Martha, her teacher at school, interacted with Sayuri, s

Leona [35]

I think the answer to this question is A because she acts differently from the other children

6 0

3 years ago

Read 2 more answers

Suppose a fireworks shell explodes, breaking into three large pieces for which air resistance is negligible. How is the motion o

denis-greek [22]

The center of mass isn't affected by the explosion.

To find the answer, we need to know about the trajectory of motion at zero external force.

<h3>How is the trajectory of an object changed when the net external force on it is zero?</h3>

When there's no net external force acting on an object, its momentum doesn't change with time.
As its momentum doesn't change, so it continues with the original trajectory.

<h3>Why doesn't the trajectory of firework change when it's exploded?</h3>

When a firework is exploded, its internal forces are changed, but there's no external force.
So, although the fragments follow different trajectories, but the trajectory of center of mass remains unchanged.

Thus, we can conclude that the center of mass isn't affected by the explosion.

Learn more about the trajectory of exploded firework here:

brainly.com/question/17151547

#SPJ4

3 0

2 years ago

Athlete meseret defar runs at 10m​

Athlete meseret defar runs at 10m