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alex41 [277]
3 years ago
7

The difference between tension and traction?

Physics
1 answer:
Kitty [74]3 years ago
3 0
The object may not end up in motion - either if tension is balanced in opposite directions, or if traction is greater than tension.
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In the aftermath of an intense earthquake, the earth as a whole "rings" with a period of 54 minutes.
lawyer [7]

The frequency of the oscillation in hertz is calculated to be 0.00031 Hz.

The frequency of a wave is defined as the number of cycles completed per second while the period refers to the time taken to complete a cycle. The frequency is the inverse of period.

So;

Period(T) = 54 minutes or 3240 seconds

Frequency (f) = T-1 = 1/T = 1/3240 seconds = 0.00031 Hz

Learn more: brainly.com/question/14588679

6 0
2 years ago
Which of the following is true about all electromagnetic waves in a vacuum
Helen [10]
Electro waves in a vacuum air is deals with this and electricity when the air and the electricity it  makes electro magnets.
4 0
3 years ago
Read 2 more answers
If the fundamental frequency of a musical instrument is 42Hz, what is the frequency of the second harmonic?
timurjin [86]
For the majority of instruments f = n f0 where f is the resonating frequency, n is any whole number and f0 is the fundamental. 
<span>This applies to trumpets, violins, flutes and a broad range. </span>
<span>In such a </span>case<span> the first harmonic would be at n=1 and the second harmonic would be at n=2 </span>

<span>which gives a frequency of 84 Hz</span>
7 0
3 years ago
consider a solid sphere and a solid disk wiht the same radius and the same mass. explain why the solid disk has a greater moment
andriy [413]

Answer:

Moment of inertia of the solid sphere:

I

s

=

2

5

M

R

2

.

.

.

.

.

.

.

.

.

.

.

(

1

)

Is=25MR2...........(1)

Here, the mass of the sphere is

M

M

4 0
3 years ago
A flywheel with a radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.600 rad/s2. Compu
boyakko [2]

Answer:

0.42 m/s²

Explanation:

r = radius of the flywheel = 0.300 m

w₀ = initial angular speed = 0 rad/s

w = final angular speed = ?

θ = angular displacement = 60 deg = 1.05 rad

α = angular acceleration = 0.6 rad/s²

Using the equation

w² = w₀² + 2 α θ

w² = 0² + 2 (0.6) (1.05)

w = 1.12 rad/s

Tangential acceleration is given as

a_{t} = r α = (0.300) (0.6) = 0.18 m/s²

Radial acceleration is given as

a_{r} = r w² = (0.300) (1.12)² = 0.38 m/s²

Magnitude of resultant acceleration is given as

a = \sqrt{a_{t}^{2} + a_{r}^{2}}

a = \sqrt{0.18^{2} + 0.38^{2}}

a = 0.42 m/s²

8 0
3 years ago
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