Answer:
The direction the plane would have to fly to compensate for a wind velocity of 62.0 km/h[N] is 4.5° S of W
Explanation:
The given parameters are;
Velocity of Jet = 792 km/h
Direction of jet velocity = West
Velocity of wind = 62.0 km/h
Direction of wind velocity = North
Therefore, the jet has to have a component of 62.0 km/h South of West to compensate for the wind velocity
The direction of the plane, θ° South of West (S of W) to compensate for the wind is given as follows;
Therefore;
The direction the plane would have to fly to compensate for a wind velocity of 62.0 km/h[N] = 4.5° S of W.