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Zigmanuir [339]

3 years ago

13

A large insulating sheet has a surface charge density σ. what is the electric field strength near the insulating sheet?

1 answer:

MakcuM [25]3 years ago

3 0

Free insulative sheets and insulative sheets backed by a grounded conductor are the only cases in which it is possible to extract reliable information from a noncontacting measurement of the charged state of an insulator. In both cases, the electric field from the charge is the deciding factor.<span>

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zavuch27 [327]

Answer:

D

Explanation:

a neutron does not have a positive nor negative charge it remains neutral

6 0

3 years ago

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A professional cyclist rides a bicycle that is 92 percent efficient. For every 100 joules of energy he exerts as input work on t

emmainna [20.7K]

Efficiency = Work Output / Work Input

92% = Work Output / 100

0.92 = Work Output / 100

Work Output = 0.92 * 100

Work Output = 92 joules.

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3 years ago

You are walking in Paris alongside the Eiffel Tower and suddenly a croissant falls on your head and knocks you to the ground. If

Alexxandr [17]

Answer:

7,79 seconds

Explanation:

${\overline {a}}={\frac {\Delta v}{t}}$

You need to use the acceleration formula. A is acceliration, $\displaystyle \Delta \mathbf {v}$ is change in velocity and t is time.

You need to multiply the formula with t and divide by a and you get

a*t= $\displaystyle \Delta \mathbf {v}$

t= $\displaystyle \Delta \mathbf {v}$ /a

after that you just need to insert the numbers

change in velocity is 76.4 minus 0.

acceliration is gravitational acceleration which is 9.81.

After that you get

t=76.4/9.81

t= 7,787971458 s

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3 years ago

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Two charges of equal magnitude Q are held a distance d apart. Consider only points on the line passing through both charges.For

Burka [1]

Answer:

A

Explanation:

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3 years ago

An ideal heat engine absorbs 97.2 kJ of heat and exhausts 83.8 kJ of heat in each cycle. What is the efficiency of the engine?

r-ruslan [8.4K]

Answer:

13.7%

Explanation:

Given that,

Heat absorbed by the engine = 97.2 kJ

Heat exhausted by the engine in each cycle = 83.8 kJ

We need to find the efficiency of the engine. It is calculated by the formula.

$\eta=1-\dfrac{Q_e}{Q_a}\\\\=1-\dfrac{83.8}{97.2}\\\\=0.137\\\\=13.7\%$

so, the efficiency of heat engine is 13.7%.

5 0

3 years ago