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3 years ago

A large insulating sheet has a surface charge density σ. what is the electric field strength near the insulating sheet?

1 answer:

3 0

Free insulative sheets and insulative sheets backed by a grounded conductor are the only cases in which it is possible to extract reliable information from a noncontacting measurement of the charged state of an insulator. In both cases, the electric field from the charge is the deciding factor.<span>

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A cardboard box has four forces acting upon it, as shown in the diagram below. What is the magnitude of the unknown force, Funkn

AlekseyPX

Answer:

D) 11 N

Explanation:

F = mg

In the vertical

30 = m(9.8)

m = 3.06 kg

in the horizontal

F = ma

F(unknown) - 5 = 3.06(2.0)

F(unknown) = 11.12... N

5 0

3 years ago

Two objects made of the same material are heated to 60 oC and 90 oC. According to

nlexa [21]

Assuming that there is in a vacuum, the two object will cool at the same rate, because the objects are made of the same material they will have the same cooling rate, assuming the surrounding temperature is the same.

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3 years ago

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Black holes are highly condensed remnants of stars. Some black holes, together with a normal star, form binary systems. In such

borishaifa [10]

$\lambda_\text{max} = 2.63\times 10^{-9}\;\text{m}$ .

<h3>Explanation</h3>

The peak emission wavelength of an object depends on its absolute temperature.

$\lambda_\text{max} = \dfrac{2.90\times 10^{-3}}{T}$ ,

where

$\lambda_\text{max}$ is the wavelength in meters where the emission is the strongest.
$T$ is the temperature of the object in degrees Kelvins.

For the gas falling into the black hole,

$T = 1.10\times 10^{6}\;\text{K}$ .

Apply the formula:

$\lambda_\text{max} = \dfrac{2.90\times 10^{-3}}{T} = \dfrac{2.90\times 10^{-3}}{1.10\times 10^{6}} = 2.64\times 10^{-9}\;\text{m} = 2.64 \;\text{nm}$ .

The question mentioned that $\lambda_\text{max}$ is in the X-ray region of the electromagnetic spectrum. According to Encyclopedia Britannica, the wavelength of X-rays range from $10^{-8}\;\text{m}=10\;\text{nm}$ to $10^{-10}\;\text{m} = 0.1\;\text{nm}$ , which indeed includes $2.64\times 10^{-9}\;\text{m} = 2.64 \;\text{nm}$ .

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3 years ago

A fire engine is rapidly approaching you at a stop light. What happens to the frequency and pitch of the sound as the fire engin

ValentinkaMS [17]

Answer:

The frequency increases, and the pitch increases

Explanation:

Doppler's law of sound is applicable in such case when the observer or the sound source or both are moving relative to each other.

In such a case due to space-time constraint the waveform of the sound adjust themselves so as to obey the law of conservation of energy.

<u>The apparent frequency of the sound for the observer is given by:</u>

$f_o=(\frac{s+v_o}{s+v_s} )f$ ....................................(1)

where:

$f_o=$ observed frequency

$f=$ original source frequency

$s=$ speed of sound

$v_s=$ speed of source relative to the observer (taken negative when approaching towards the observer and vice-versa)

$v_o=$ speed of observer relative to the source (taken negative when moving away from the source and vice-versa)

<u>According to the given situation, eq. (1) becomes:</u>

$f_o=(\frac{s}{s-v_s} )f$

Since, $\frac{s}{s-v_s} >1$

Therefore

$f_o>f$

Pitch is very closely related to the frequency, it means that how fast is the amplitude of sound varying with time.

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3 years ago

Consider two objects of the same mass. If a force of 100N acts on the first for a duration of 1s and on the other for a duration

kompoz [17]

So velocity=displacement/time and force=mass*acceleration. Both objects have the same acceleration because the amount of time doesn’t play a role in the equation. Momentum equation is p=mv so only the mass and overall velocity matter. Therefore, the answer is c because time is not a variable

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3 years ago

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