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nataly862011 [7]
3 years ago
11

A car with a mass of 860 kg sits at the top of a 32 meter high hill. Describe the transformations between potential and kinetic

energy that occur when the car rolls to the bottom of the hill and continues rolling.
Physics
1 answer:
I am Lyosha [343]3 years ago
5 0

Answer:

Kinetic energy at the bottom equals potential energy at the top hence 269971.2  J

Explanation:

Assuming no friction and neglecting air resistance, from the law of conservation of energy, the potential energy that the car posses at 32 m is all converted to kinetic energy hence

PE= mgh

KE= 0.5mv^{2}

Here m denotes the mass of the car, g is acceleration due to gravity, h is the height and v is the speed of the car

The potential energy will be PE= 860*9.81*32=269971.2  J

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Answer:

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r =  \sqrt{50 - 40.71}  =  \sqrt{9.29}

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6 0
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Answer:

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6 0
3 years ago
Which one of the following is a derived SI unit?<br>A.newton B.meter C.mole d.Kilogram ​
marusya05 [52]

Answer:

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Explanation:

I'd say meters, cause it's the SI unit of length,

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5 0
3 years ago
Dillon wants to go to the park to play basketball. To get to the park, he must travel 9 km East, and then 6 km South, then 9 Km
puteri [66]

Answer:

24 km

Explanation:

9 + 9 + 6 = 24

5 0
3 years ago
Please help, and show steps. Thank you very much!
Vikentia [17]
V = 8 * 10^2 km/h = 800km/h
S= 1,8* 10^3 km = 1800km
t = ?
v = S/t
t = S/v
t = 1800km/ 800km/h
t ≈ 2,25h (135min)
6 0
3 years ago
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