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nataly862011 [7]
3 years ago
11

A car with a mass of 860 kg sits at the top of a 32 meter high hill. Describe the transformations between potential and kinetic

energy that occur when the car rolls to the bottom of the hill and continues rolling.
Physics
1 answer:
I am Lyosha [343]3 years ago
5 0

Answer:

Kinetic energy at the bottom equals potential energy at the top hence 269971.2  J

Explanation:

Assuming no friction and neglecting air resistance, from the law of conservation of energy, the potential energy that the car posses at 32 m is all converted to kinetic energy hence

PE= mgh

KE= 0.5mv^{2}

Here m denotes the mass of the car, g is acceleration due to gravity, h is the height and v is the speed of the car

The potential energy will be PE= 860*9.81*32=269971.2  J

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when approaching the front of an idling jet engine, the hazard area extends forward of the engine approximately
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7 0
1 year ago
Objects 1 and 2 attract each other with a electrostatic force of 72.0 units. If the distance separating objects 1 and 2 is chang
qaws [65]

Answer:

288.0 units; that is the electrostatic force of attraction become quadruple of its initial value.

Explanation:

If all other parameters are constant,

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If r₁ = r/2, what happens to F₁

F₁ = (k/r₁²) = k/(r/2)² = (4k/r²) = 4F = 4 × 72 = 288.0 units

5 0
3 years ago
Read 2 more answers
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