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neonofarm [45]
3 years ago
14

What volume (in mL) of a 0.150 M HNO 3 solution will completely react with 35.7 mL of a 0.108 M Na 2 CO 3 solution according to

this balanced chemical equation?
Na 2 CO 3 ( a q ) + 2 HNO 3 ( a q ) → 2 NaNO 3 ( a q ) + CO 2 ( g ) + H 2 O ( l )
Chemistry
1 answer:
iogann1982 [59]3 years ago
3 0

Answer:

The answer to your question is 51.4 ml

Explanation:

Data

HNO₃ = 0.150 M;  Volume = ?

Na₂CO₃ = 0.108 M; Volume = 35.7 ml

Process

1.- Calculate number of moles of Na₂CO₃

Molarity = \frac{moles}{volume}

moles = Molarity x volume

moles = 0.108 x 0.0357

moles = 0.00386

2.- From the equation we know that 1 mol of Na₂CO₃ reacts with 2 moles of HNO₃.

                                   1 mol of Na₂CO₃ -------------  2 moles of HNO₃

                             0.00386 mol of Na₂CO₃ ------    x

                            x moles of HNO₃ = (0.00386 x 2) / 1

                               moles of HNO₃ = 0.00771

3.- Calculate the volume of HNO₃ used

volume = \frac{moles}{molarity}

volume = \frac{0.00771}{0.150}

volume = 0.0514 l

volume = 51.4 ml

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dolphi86 [110]

Answer:

= 97.44 Liters at S.T.P

Explanation:

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From the reaction when the reactants react, 2 moles of Fe and 3 moles of CO2 are produced.

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6 0
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