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Y_Kistochka [10]
3 years ago
5

Which is the correct net ionic equation for the following reaction: 2 HBr (aq) + Co(OH)2 (aq) Imported Asset CoBr2 (aq) + 2 H2O

(l)?
A. H+ (aq) + OH− (aq) Imported Asset H2O (l)

B. Co(OH)2 (aq) Imported Asset Co+2 (aq) + OH− (aq)

C. 2 H+ (aq) + Co(OH)2 (aq) Imported Asset Co+2 (aq) + 2 H2O (l)

D. 2 HBr (aq) + Co(OH)2 (aq) Imported Asset CoBr2 (aq) + 2 H2O (l)
Chemistry
1 answer:
kow [346]3 years ago
6 0

its B why because the reaction is good with B

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2. How much heat is released when 432g of water cools down from 710C to 180C?
nadya68 [22]
The heat released by the water when it cools down by a temperature difference AT

is Q = mC,AT

where

m=432 g is the mass of the water

C, = 4.18J/gºC

is the specific heat capacity of water

AT = 71°C -18°C = 530

is the decrease of temperature of the water

Plugging the numbers into the equation, we find

Q = (4329)(4.18J/9°C)(53°C) = 9.57. 104J

and this is the amount of heat released by the water.
7 0
3 years ago
1. Is O2 a compound? Explain.
zhuklara [117]
1. O2 is not a compound because it only contains one or more type of the same element atom.
2. O2 is a molecule because a molecule is one or more of the same element atom.
3. The law of conversion is that the mass of the system will stay the same when transfer takes place. Like if you had an equation O+H2—> H2O the mass will remain the same.

4. It will be equal to 10 because of law of conservation of matter.

5. One observation can be that the compound, reaction you’re observing, has change states.

4 0
3 years ago
30 POINTS! ----- How many moles of oxygen gas are needed to completely react with 145 grams of aluminum? Report your answer with
gladu [14]
First a balanced reaction equation must be established:
4Al _{(s)}    +   3 O_{2}  _{(g)}     →    2 Al_{2} O_{3}

Now if mass of aluminum = 145 g
the moles of aluminum = (MASS) ÷ (MOLAR MASS) = 145 g ÷ 30 g/mol
                                                                                    =  4.83 mols

Now the mole ratio of Al : O₂ based on the equation is  4 : 3  
                                                                [4Al  + 3 O₂ → 2 Al₂O₃]

∴ if moles of Al = 4.83 moles
  then moles of O₂ = (4.83 mol ÷ 4) × 3
                              =  3.63 mol   (to  2 sig. fig.) 

Thus it can be concluded that 3.63 moles of oxygen is needed to react completely with 145 g of aluminum. 


     
4 0
4 years ago
Describe how to test your unknown salt mixture for the presence of<br>Na3PO4.12H2O.​
klemol [59]

Na3PO4*12H2O + BaCl2*2H2O = Ba3(PO4)2 + NaCl + H2O

add barium chloride to your Na3PO4.12H2O a white precipitate of Ba3(PO4)2 will be formed wrt salt(NaCl) and water(H20) if Na3PO4.12H2O. will be there.

6 0
3 years ago
.ASAPPP
kati45 [8]

Answer:

b

Explanation:

5 0
3 years ago
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