No se :/, a ti si te paso??
Answer:
The answer to your question is:
Vol of NO2 = 11.19 L
Vol of O2 = 2.8 L
Explanation:
Data
N2O5 = 56 g
STP T = 0°C = 273°K
P = 1 atm
MW N2O5 = 216 g
Gases law = PV = nRT
Process
216 g of N2O5 ---------------- 1 mol
54 g ----------------- x
x = (54 x 1) / 216
x = 0.25 mol of N2O5
2 mol of N2O5 ----------------- 4 mol of NO2
0.25 mol ------------------ x
x = (0.25 x 4) / 2 = 0.5 mol of NO2
V = nRT/P
V = (0.5)(0.082)(273) / 1 = 11.19 L
2 mol of N2O5 ----------------- 1 O2
0.25 N2O5 ---------------------- x
x = (0.25 x 1) / 2 = 0.125 mol
Vol = (0.125)((0.082)(273) / 1 = 2.8 L
Answer:
C. Chain Reaction
Explanation:
You get different elements from just one by a single reaction.
Answer:
i know it is alot but that is how are teacher told us to do, hope this is correct
Explanation:
a. 2.6
b. 12.0
Explanation:
a.
First, we will calculate the molar concentration of HCl.
M = mass of HCl / molar mass of HCl × liters of solution
M = 0.40 g / 36.46 g/mol × 4.5 L
M = 2.4 × 10⁻³ M
HCl is a strong monoprotic acid, so [H⁺] = 2.4 × 10⁻³ M. The pH is:
pH = -log [H⁺]
pH = -log 2.4 × 10⁻³ = 2.6
b.
First, we will calculate the molar concentration of NaOH.
M = mass of NaOH / molar mass of NaOH × liters of solution
M = 0.80 g / 40.00 g/mol × 2.0 L
M = 0.010 M
NaOH is a strong base with 1 OH⁻, so [OH⁻] = 0.010 M. The pOH is:
pOH = -log [OH⁻]
pOH = -log 0.010 = 2.0
The pH is:
14.00 = pH + pOH
pH = 14.00 - pOH = 14.00 - 2.0 = 12.0
