It's 4. The factors of 12 are: 1,2,3,4,6,12. The factors of 20 are: 1,2,4,5,10,20.
Answer:
SITE A
Step-by-step explanation:
Given :
proposed-site Area-Served
1 2 3 4
A 5.2 4.4 3.6 6.5
B 6.0 7.4 3.4 4.0
C 5.8 5.9 5.9 5.8
D 4.3 4.8 6.5 5.1
Area 1 2 3 4
Number-runs 150 65 175 92
Computing the weighted average for the 4 sites :
Site A:
((150*5.2) + (65*4.4) + (175*3.6) + (92*6.5)) / (150 + 65 + 175 + 92)
= 2294 / 482
= 4.7593
Site B:
((150*6.0) + (65*7.4) + (175*3.4) + (92*4.0)) / (150 + 65 + 175 + 92)
= 2344/ 482
= 4.863
Site C:
((150*5.8) + (65*5.9) + (175*5.9) + (92*5.8)) / (150 + 65 + 175 + 92)
= 2819.6/ 482
= 5.850
Site D:
((150*4.3) + (65*4.8) + (175*6.5) + (92*5.1)) / (150 + 65 + 175 + 92)
= 2563.7/ 482
= 5.319
From the weighted average response time computed for the different sites ;
The best location for the emergency facility would be one with the least average response time; which is SITE A.
Answer:
60%
Step-by-step explanation:
Answer:
Y=4X+2
Y=4X
4X/2
4*2+2=Y
Y=2
Step-by-step explanation:
Carlos is correct
Since we don't know the length of sides PR and XZ, the triangles can't be congruent by the SSS theorem or the SAS theorem, and since we don't know the measure of angles Y and Q, the triangles can't be congruent by the ASA theorem, the SAS theorem or the AAS theorem. Therefore, Carlos is correct.
Carlos is correct. Since the angles P and X are not included between PQ and RQ and XY and YZ, the SAS postulate cannot be used, since it states that the angle must be included between the sides. Unlike with ASA, where there is the AAS theorem for non-included sides, there is not SSA theorem for non-included angles, so the triangles cannot be proven to be congruent.
