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2 years ago

Find the exact solution using common logarithms 2^5x+3= 3^2x+1

1 answer:

6 0

$2^{5x + 3} = 3^{2x + 1}$
$log_{2}(2^{5x + 3}) = log_{2}(3^{2x + 1})$
$(5x + 3)log_{2}(2) = (2x + 1)log_{2}(3)$
$5x + 3 = 1.58(2x + 1)$
$5x + 3 = 3.16x + 1.58$
$1.84x + 3 = 1.58$
$1.84x = -1.42$
$x \approx -0.77$

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Complete the set of ordered pairs for the relation.

Nonamiya [84]

The set of ordered pairs are $(-2,18),(-1,20),(0,22),(1,24),(2,26)$

Step-by-step explanation:

Given that the relation $\{(x, y): y=2(x+11) \text { and } x \in(-2,-1,0,1,2)\}$

To find the set of ordered pairs, let us substitute the value for x in the relation $y=2(x+11)$

For $x=-2$ ,

$\begin{aligned}y &=2(-2+11) \\&=2(9) \\y &=18\end{aligned}$

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For $x=-1$ ,

$\begin{aligned}y &=2(-1+11) \\&=2(10) \\y &=20\end{aligned}$

The ordered pair is $(-1,20)$

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$\begin{aligned}y &=2(0+11) \\&=2(11) \\y &=22\end{aligned}$

The ordered pair is $(0,22)$

For $x=1$ ,

$\begin{aligned}y &=2(1+11) \\&=2(12) \\y &=24\end{aligned}$

The ordered pair is $(1,24)$

For $x=2$ ,

$\begin{aligned}y &=2(2+11) \\&=2(13) \\y &=26\end{aligned}$

The ordered pair is $(2,26)$

Thus, the set of ordered pairs is $(-2,18),(-1,20),(0,22),(1,24),(2,26)$

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2 years ago

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MatroZZZ [7]

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Choice A is ruled out as well because we have both pairs of opposite sides that are parallel. The only thing left is choice D. This is true assuming we have a square prism. Any cube is a square prism that has its height equal to the width and length.

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