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2 years ago

Helpppp plzzzzzzzzzzzzzzzz

Mathematics

1 answer:

mariarad [96]2 years ago

8 0

I’m a bit confused by the choices you have been given. Are there any other options? If not, I would choose (5.3,9.8) as 9.8 is correct

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Isabel is using the TVM Solver on her graphing calculator as shown below to determine how much she has to invest now in a saving

Finger [1]

Answer:

C monthly

Step-by-step explanation:

Apex

3 0

2 years ago

suppose 60% of kids who visit a doctor have a fever, and 20% of kids with a fever have sore throats. what's the probability that

kkurt [141]

Answer:

0.12

Step-by-step explanation:

Suppose there are 100 kids

60% have fever, so what is 60% of 100?

We convert percentage to decimal and multiply:

60/100 = 0.6

0.6 * 100 = 60 have fever

20% of the people having fever (60 of them) have sore throats, so,

What is 20% of 60?

We convert percentage to decimal and multiply:

20/100 = 0.2

0.2 * 60 = 12 have sore throat

So, how many people are there with fever AND sore throat, that is 12. We took initially there to be 100 people. Hence, the probability is:

$\frac{12}{100}=0.12$

3 0

2 years ago

Solve using Quadratic Formula x^2 + 3x - 3 = 0

katrin [286]

Answer:

a= 1 , b= 3 , c= –3

$x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - 3 \frac{ + }{} {} \sqrt{ {3}^{2} - 4(1)( - 3)} }{2(1)} \\ = \frac{ - 3 \frac{ + }{} \sqrt{9 + 12} }{2} = \frac{ - 3 \frac{ + }{} \sqrt{21} }{2} \\ \\ x = \frac{ - 3 \frac{ + }{} \sqrt{21} }{2} \\ \\ x = 0.79 \\ x = - 3.79$

I hope I helped you^_^

4 0

2 years ago

Find the probability that the mean annual preciptiation will be between 32 and 34 inches. variable is normally distributed

liq [111]

Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.

This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.
34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
1.9
32 in - 31.2 in
and that to the left of 32 in is z = ---------------------- = 0.421
1.9

Know how to use a table of z-scores to find these two areas? If not, let me know and I'll go over that with you.

My TI-83 calculator provided the following result:

normalcdf(32, 34, 31.2, 1.9) = 0.267 (answer to this sample problem)

5 0

2 years ago

Please help, AND READ DIRECTIONS, get done as soon as possible.

katen-ka-za [31]

Answer:

IT would be 13a to 17b

Step-by-step explanation:

I had this.

7 0

2 years ago