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The rate at which the ice changes is -3/8 lb per hr
<h3>What is the rate the ice changes?</h3>
The given parameters are:
Changes =1 3/4 lb to 1/4 lb
Time = 1/4 hr.
The rate the ice changes is calculated as:
Rate = Change/Time
So, we have
Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)
Evaluate the difference
Rate = (-1 1/2 lb)/(1/4 hr)
Evaluate the quotient
Rate = -3/8 lb per hr
Hence, the rate at which the ice changes is -3/8 lb per hr
Read more about rates at:
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5pi/12 radians
The arc measure is 75, so theta must also be the same. if theta is 75, and 75 in radians is 5pi/12 radians, then the answer is that.
It Does Not Matter Where You Put The Line, As The Slope Stays The Same. So, We Can Say That One Point Is (3,0)
(3,0) and (6,6)
So, The Slope Is 2.
Answer:
x > -6.
Step-by-step explanation:
2x + 3 > -9
2x > -9 - 3
x > -12/2
x > -6.
