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Crazy boy [7]
3 years ago
7

Once the cell cycle begins, there are built-in ____________________ that can stop it at any time.

Biology
1 answer:
iogann1982 [59]3 years ago
5 0
<span>Once the cell cycle begins, there are built-in CHECK POINTS that can stop it at any time.</span>
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Heterozygotes at the sickle-cell locus produce both normal and abnormal (sickle-cell) hemoglobin (see Concept 11.4). When hemogl
Stels [109]

Answer:

In an individual's molecular and cellular level, the heterozygote alleles are preferred over the homozygote alleles. In humans, the heterozygote alleles are found at a locus of beta polypeptide subunit of hemoglobin, while on the other hand, the homozygous alleles found at a similar locus are prone to sickle cell disease.  

The individuals carrying homozygous alleles exhibit sickle-shaped RBCs and they also possess low oxygen-carrying capacity, which ultimately results in brain, kidney, or heart failure. However, in the case of heterozygous alleles, the configurations of RBCs are of two kinds, that is, normal shaped and sickle-shaped. Thus, there are not enough sickle-shaped cells to result in the condition.  

The heterozygote alleles are resistant to malaria, thus, in tropical areas, where malaria is a prime issue the heterozygote alleles are preferred over the homozygote dominant alleles as they are vulnerable to the infection and over the homozygote recessive alleles who has sickle cell disease.  

6 0
3 years ago
The coconut palm is now widely dispersed in the world because of ________.
Vedmedyk [2.9K]
Birds because they spread seeds
3 0
3 years ago
Tay-Sachs disease is a lethal, autosomal recessive genetic disorder. If both parents are heterozygous carriers of the disease, w
rjkz [21]

Answer:

50%

Explanation:

Let's assume that the allele "T" gives the normal phenotype while the recessive allele "t" imparts the disease and is lethal in homozygous condition. The genotype of each of the two carrier parents would be "Tt". A cross between Tt and Tt would give the progeny in the following genotype ratio=

Tt x Tt= 1/4 TT: 1/2 Tt: 1/4 tt

Therefore, 1/2 or 50% progeny would be the carrier for the Tay-Sachs disease.

4 0
3 years ago
Do you think Peacocks would be in Hardy-Weinberg Equilibrium? Why or why not?
Slav-nsk [51]

Peacocks would not be in Hardy-Weinberg Equilibrium

Explanation:

This can be justified by the mating patterns of the female peacocks. They do not choose their mates randomly but look out specifically for bright attractive plumage in their male partners and then select them.

Hardy-Weinberg's Equilibrium of evolution mechanism was based on facts like random mating, no natural selection,  mutation, absence of gene flow, and infinite population size.

They stated that organisms mate randomly with each other without any specific or a particular preference in the phenotypes of their opposite mates

4 0
3 years ago
Asexual reproduction involves
Semenov [28]
A. Asexual reproduction is like cloning.
8 0
2 years ago
Read 2 more answers
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