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4 years ago

I’ll give you best answer and a thanks plsplspls help i’m legit freaking out i keep getting decimals

Mathematics

1 answer:

earnstyle [38]4 years ago

6 0

First, find R angle at TRS = 180-(10x+13)
then you know that total angles of a triangle is 180 so
TRS+RST+STR
180-(10x+13) + 8x+1 + 34 = 180
180-10x-13+8x+1+34 = 180
-13+1+34 = 10x-8x
22 = 2x
then x = 11

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nevsk [136]

Step-by-step explanation:

9 = a7 + b

-2 = a9 + b

b = 9-7a and b = - 2-9a

9 - 7a = - 2-9a

2a = - 11

a = - 5.5

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3 years ago

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3 years ago

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3 years ago

Write an equation that is perpendicular to and 3x+y=3 whose y-intercept 5. Anyone please help me, no link just explain how to do

Liula [17]

Answer:

$y = \frac{1}{3}x + 5$

Step-by-step explanation:

By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other: $m = - \frac{1}{m_{2} }$ , or equivalently, $m_{1} * m_{2} = -1$ .

Given our linear equation 3x + y = 3 (or y = -3x + 3):

We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is $\frac{1}{3}$ .

To test whether this is correct, we can take first slope, $m_{1} = -3$ , and multiply it with the negative reciprocal slope $m_{2} = \frac{1}{3}$ :

$m_{1} * m_{2} = -1$

$-3 * \frac{1}{3} = -1$

Therefore, we came up with the correct slope for the other line, which is $\frac{1}{3}$ .

Finally, the y-intercept is given by (0, 5). Therefore, the equation of the line that is perpendicular to 3x + y = 3 is:

$y = \frac{1}{3}x + 5$

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3 years ago