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In-s [12.5K]
3 years ago
10

Find the unit rate: 91 miles with 3.5 gallons of gas

Mathematics
1 answer:
lawyer [7]3 years ago
4 0

the answer is 26... just divide!

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Piper wants to buy enough potting soil to fill flower box that is 36 inches long, 8 inches wide, and 10 inches tall. If one bag
cupoosta [38]

Answer:

5

Step-by-step explanation:

We gonna multiply the 36 inches long, 8 inches wide and 10 inches tall and divide it by no of bag (576)

4 0
3 years ago
Between what two consecutive integers is the square root of 29
lina2011 [118]

Answer: 5 and 6

Step-by-step explanation:

sqrt1=1

sqrt4=2

sqrt9=3

sqrt16=4

sqrt25=5

sqrt29~5.4

sqrt36=6

3 0
3 years ago
Read 2 more answers
An architect is designing a new library. The library’s floor plan is a rectangle divided into a bookshelf space with bookshelves
Luda [366]

Answer:

the answer is 19/84

Step-by-step explanation:

hope this helps

4 0
3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 9t + 9 cot(t/2), [π/4, 7π/4]
agasfer [191]

Answer:

the absolute maximum value is 89.96 and

the absolute minimum value is 23.173

Step-by-step explanation:

Here we have cotangent given by the following relation;

cot \theta =\frac{1 }{tan \theta} so that the expression becomes

f(t) = 9t +9/tan(t/2)

Therefore, to look for the point of local extremum, we differentiate, the expression as follows;

f'(t) = \frac{\mathrm{d} \left (9t +9/tan(t/2)  \right )}{\mathrm{d} t} = \frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2}

Equating to 0 and solving gives

\frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2} = 0

t=\frac{4\pi n_1 +\pi }{2} ; t = \frac{4\pi n_2 -\pi }{2}

Where n_i is an integer hence when n₁ = 0 and n₂ = 1 we have t = π/4 and t = 3π/2 respectively

Or we have by chain rule

f'(t) = 9 -(9/2)csc²(t/2)

Equating to zero gives

9 -(9/2)csc²(t/2) = 0

csc²(t/2)  = 2

csc(t/2) = ±√2

The solutions are, in quadrant 1, t/2 = π/4 such that t = π/2 or

in quadrant 2 we have t/2 = π - π/4 so that t = 3π/2

We then evaluate between the given closed interval to find the absolute maximum and absolute minimum as follows;

f(x) for x = π/4, π/2, 3π/2, 7π/2

f(π/4) = 9·π/4 +9/tan(π/8) = 28.7965

f(π/2) = 9·π/2 +9/tan(π/4) = 23.137

f(3π/2) = 9·3π/2 +9/tan(3·π/4) = 33.412

f(7π/2) = 9·7π/2 +9/tan(7π/4) = 89.96

Therefore the absolute maximum value = 89.96 and

the absolute minimum value = 23.173.

7 0
4 years ago
a storage jug was 4/5 full of water when did get indicated 72 what was the full capacity of the storage jug​
IRISSAK [1]

Answer:

<em><u>9</u></em><em><u>0</u></em><em><u>. </u></em><em><u>(</u></em><em><u> </u></em><em><u>was </u></em><em><u>the </u></em><em><u>full </u></em><em><u>capacity</u></em><em><u> of</u></em><em><u> </u></em><em><u>jug</u></em><em><u>)</u></em>

<em><u>to </u></em><em><u>solve </u></em><em><u>this</u></em><em><u> </u></em>

<em><u>firstly</u></em><em><u> </u></em><em><u>let </u></em><em><u>the </u></em><em><u>full </u></em><em><u>capacity</u></em><em><u> </u></em><em><u>of </u></em><em><u>jug </u></em><em><u> </u></em>

<em><u> </u></em><em><u> </u></em>

<em><u>be</u></em><em><u>. </u></em><em><u>x</u></em>

<em><u>so,</u></em><em><u> </u></em>

<em><u>4</u></em><em><u>/</u></em><em><u>5</u></em><em><u>*</u></em><em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u>2</u></em>

<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u>2</u></em><em><u>*</u></em><em><u>5</u></em><em><u>/</u></em><em><u>4</u></em>

<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>9</u></em><em><u>0</u></em>

<em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em>

6 0
3 years ago
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