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Dovator [93]
3 years ago
9

Solve for x: 5(x + 3) = 4(x − 3)

Mathematics
2 answers:
OLEGan [10]3 years ago
8 0

Answer:

x = -27

Step-by-step explanation:

Step  1  :

Equation at the end of step  1  :

 (5 • (x + 3)) -  4 • (x - 3)  = 0

Step  2  :

Equation at the end of step  2  :

 5 • (x + 3) -  4 • (x - 3)  = 0

Step  3  :

Equation at the end of step  3  :

 x + 27  = 0

Step  4  :

Solving a Single Variable Equation :

4.1      Solve  :    x+27 = 0

Subtract  27  from both sides of the equation :

                     x = -27

One solution was found :

                  x = -27

Processing ends successfully

plz mark me as brainliest :)

Evgen [1.6K]3 years ago
3 0

Answer:

5(x + 3) = 4(x - 3) \\ 5x + 15 = 4x - 12 \\ 5x - 4x =  - 15 - 12 \\ x =  - 27

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Answer:

Please find the answer in the image attached

Step-by-step explanation:

Here we are asked to solve a pair of linear inequalities.

In order to do so , we are first required to plot the two lines with inequalities taking into considerations.

Hence let us plot

x+2y=-4 and 5x+2y=4

let us first plot x+2y=-4

y=\frac{-4-x}{2}

let us plot a table for the same for two random values of x and putting them into above equation

x     y

0    -2

2    -3

Let us now plot these points and join the line .

Let us check whether (0,0) satisfies the in equation or not

0+2(0)≤-4

0≤-4

Which is not true , Hence we shade the portion divided by our line which does not contain (0,0)

Now let us plot the second line 5x+2y=4

y = \frac{4-5x}{2}

let us plot a table for the same for two random values of x and putting them into above equation

x     y

0     2

1     -0.5

Let us now plot these points and join the line .

Let us check whether (0,0) satisfies the in equation or not

5(0)+2(0)≤4

0≤4

Which is true , Hence we shade the portion divided by our line which does  contain (0,0)

Please refer to the image attached with this answer.

now the commonly shaded area as shown in the image will be our solution to the above pair of in equations.

3 0
3 years ago
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