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2 years ago

Given f(x) = 3x - 1 and g(x)= -x + 6, find f(-2) + g(5). A. -6 B. 6 C. 8

Mathematics

1 answer:

marta [7]2 years ago

5 0

Answer:

A. -6

Step-by-step explanation:

$f(x)=3x-1\\\\$

In order to find $f(-2)$ we will plugin $x=-2$

$f(-2) = 3(-2)-1\\f(-2)=(3\times(-2))-1\\f(-2)=-6-1$

$f(-2)=-7$

$g(x)=-x+6$

In order to find $g(5)$ we will plugin $x=5$

$g(5)=-5+6$

$g(5)=1$

$f(-2)+g(5)\\=-7+1\\=-6$

∴ $f(-2)+g(5)=-6$

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1 year ago

Please someone answer this please

gladu [14]

Option C:

$\frac{3 a^{2} b^{11}}{2 }$ is equivalent to the given expression.

Solution:

Given expression:

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To find which expression is equivalent to the given expression.

$$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}$

Using exponent rule: $\frac{1}{a^m}=a^{-m}, \ \ \frac{1}{a^{-m}}=a^{m}$

$$=\frac{-18 a^{-2} b^{5}a^{4} b^{6}}{-12 }$

$$=\frac{-18 a^{-2} a^{4} b^{5} b^{6}}{-12 }$

Using exponent rule: ${a^m}\cdot{a^n}=a^{m+n}$

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$$=\frac{-18 a^{2} b^{11}}{-12 }$

Divide both numerator and denominator by the common factor –6.

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$$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}=\frac{3 a^{2} b^{11}}{2 }$

Therefore, $\frac{3 a^{2} b^{11}}{2 }$ is equivalent to the given expression.

Hence Option C is the correct answer.

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