Answer:
The difference in price per ounce of the boxes is $0.03 or 3 cents.
Step-by-step explanation:
Divide each dollar amount by the ounces. The answer to $2.94 divided by 14 is 21 cents. $3.60 divided by 20 is 18 cents. Subtract 18 cents from 21 cents to get 3 cents.
In order to reduce ANY fraction to lowest terms, find any common factors
of the numerator and denominator, and divide them both by it. If they still
have a common factor, then divide them by it again. Eventually, they won't
have any common factor except ' 1 ', and then you'll know that the fraction is
in lowest terms.
Do 15 and 40 have any common factors ?
Let's see . . .
The factors of 15 are 1, 3, <em>5</em>, and 15 .
The factors of 40 are 1, 2, 4,<em> 5</em>, 8, 10, 20, and 40 .
Ah hah ! Do you see that ' <em>5</em> ' on both lists ? That's a common factor.
So 15/40 is NOT in lowest terms.
Divide the numerator and denominator both by 5 :
15 / 40 =<em> 3 / 8</em>
3 and 8 don't have any common factor except ' 1 '.
So 3/8 is the same number as 15/40, but in lowest terms.
This is an exponential function.
If x = 0, 2^x = 2^0 = 1. The beginning value of 2^x is 1 and the beginning value of 51*2^x is 51.
Make a table and graph the points:
x y=51*2^x point (x,y)
-- --------------- ---------------
0 51 (0,51)
2 51*2^2 = 51(4) = 204 (2,204) and so on.
The graph shows up in both Quadrants I and II. Its y-intercept is (0,51). Its slope is always positive.
PLEASE HELP! In a word processing document or on a separate piece of paper, use the guide to construct a two column proof proving that triangle RST is congruent to triangle RSQ given that RS ⊥ ST, RS ⊥ SQ, and ∠STR ≅ ∠SQR. Submit the entire proof to your instructor.
Given:
RS ⊥ ST
RS ⊥ SQ
∠STR ≅ ∠SQR
Prove:
△RST ≅ △RSQ
Answer:
Since it has smaller absolute and relative errors, 355/113 is a better aproximation for
than 22/7
Step-by-step explanation:
The formula for the absolute error is:
Absolute error = |Actual Value - Measured Value|
The formula for the relative error is:
Relative error = |Absolute error/Actual value|
I am going to consider the actual value of
as 3.14159265359.
In the case of 22/7:
22/7 = 3.14285714286.
Absolute error = |3.14159265359 - 3.14285714286| = 0.00126448927
Relative error = 0.00126448927/3.14159265359 = 0.00040249943 = 0.04%
In the case of 355/113
355/113 = 3.14159292035
Absolute error = |3.14159265359 - 3.14159292035| = 0.00000026676
Relative error = 0.00000026676/3.14159265359 = 0.000000085 = 0.0000085%
Since it has smaller absolute and relative errors, 355/113 is a better aproximation for
than 22/7