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Olegator [25]
3 years ago
11

Read the information and study the image.

Physics
1 answer:
erastova [34]3 years ago
4 0

Answer:

It is impossible to detect underground water from the surface. Dowsing practitioners refuse to explain their secrets.

Explanation:

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An automobile traveling 50km/hr. It decelerates at 5 meter per second square. How long will it take to stop the car? How far wil
const2013 [10]
We know, a = v/t
Here, a = 5 m/s²
v = 50 km/h= 13.88 m/s

Substitute their values into the expression:
5 = 13.88 / t
t = 13.88/5
t = 2.78 sec

Now, we know, v = d/t
13.88 = d/2.78
d = 13.88 * 2.78
d = 38.53 meter

In short, Your Answers would be:
i) It will take 2.78 sec
ii) It will travel for 38.53 m after a brakes applied.

Hope this helps!
3 0
3 years ago
The output voltage of a voltage amplifier has been found to decrease by 20% when a load resistance of 1 k is connected. What is
yKpoI14uk [10]

We use the voltage division problem  between the load resistance, amplifier output resistance as

V_{out} = V_{amlifire} \times \frac{R_{load} }{R_{load} + R_{out} }.

Here, V_{out} is the output voltage, V_{amlifire} is the amplifier voltage, R_{load} is the load resistance and R_{out} is the amplifier output resistance.

Therefore,

1-\frac{20}{100} = \frac{1 \ k\Omega }{1 \ k\Omega +R_{out} } \\\\ R_{out} = \frac{1 \ k\Omega }{0.8} -1 \ k\Omega =1250 \Omega -1000 \Omega =250 \Omega.

Thus, the amplifier output resistance is 250 \ \Omega.

4 0
3 years ago
Fuel which has tremendous highest calorific value. (11 points if u answer this)
Vitek1552 [10]

Semi anthracite has the higest which is 29.5

8 0
3 years ago
IP Standing side by side, you and a friend step off a bridge at different times and fall for 1.6 s to the water below. Your frie
ratelena [41]

The distance to the water is the same for both ... call it s meters


They both take 1.6 s to reach the water ... so t = 1.6 seconds


They both step off the bridge ... so both have an initial vertical velocity is 0 m/s


Just consider the vertical motion and take DOWN as the positive direction


a = 9.8 m/s²


s = v(i)t + (1/2)at²


s = 0 + (1/2) * 9.8 * 1.6²


s = 12.5 m ←←← Edit: Forgot to say ... that's how high the bridge is above the water




Now get the time it takes the first jumper to reach 1.8 m:


s = v(i)t + (1/2)at²


1.8 = 0 + 4.9t²


t = 0.61 s


so when the 2nd person jumps it takes the first person another 1.6 - 0.61 = 0.99 s to reach the water




Now find how far the 2nd jumper falls in 0.99 s:


s = 0 + 4.9 * 0.99²


s = 4.8 m


so the separation distance between the two jumpers when the 1st jumper hits the water is 12.5 - 4.8 = 7.7 m


6 0
3 years ago
Can you check this? Samantha swam upstream for some distance in one hour. She then swam downstream the same river for the same d
lorasvet [3.4K]
So her speed in still water will be 6mph :)

4 0
4 years ago
Read 2 more answers
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