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Nuetrik [128]
2 years ago
9

A man has a power of 90 W and mass 60 kg runs up a staircase in 40 s. If each staircase is 20cm high find the number of steps? (

physics grade 9- GRAVITATION)

Physics
1 answer:
34kurt2 years ago
4 0
I showed my working in the images above. if you have any questions please feel free to ask

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PLZ HELP I WILL GIVE BRAINLIEST
Vaselesa [24]

Answer:

12.7m/s

Explanation:

Given parameters:

Mass of diver  = 77kg

Height of jump  = 8.18m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we apply the motion equation below:

             v²   = u²  + 2gH

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

H is the height

 Now insert the parameters and solve;

       v² = 0²  +  2 x 9.8 x 8.18

     v  = 12.7m/s

8 0
2 years ago
Calculate the momentum of a 4 kg Bolling ball being thrown at a speed of 3 m/s
bonufazy [111]

We are given –

  • Mass of boiling ball is, m = 4 kg
  • Speed is, v = 3 m/s
  • Momentum, P =?

As we know –

↠Momentum = Mass × Speed(Velocity)

↠Momentum = 4 × 3 kgm/s

↠Momentum = 12 kgm/s

  • Henceforth,Momentum will be 12 kgm/s.
7 0
2 years ago
13) A branch falling from a tree is to gravity as a car driving on the road is to A) a driver's foot off of the accelerator, coa
IgorC [24]
<span>a driver's foot off the accelerator and on the break pedal. C</span>
3 0
2 years ago
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Suppose you could suddenly increase the speed of every molecule in a gas by a factor of 2. Would the gas pressure increase by a
Elena L [17]

<h2>The pressure will become double </h2>

Explanation:

The gas pressure is directly proportional to the mean root square velocity of the constituent molecules of gas .

P ∝ \sqrt{\frac{C_1^2+C_2^2+C_3^2----C_n^2}{n} }      I

Here C₁ , C₂ ------------ Cₙ is the velocities of molecules .

By making these velocities double

The pressure P₀ ∝ 2\sqrt{\frac{C_1^2+C_2^2+C_3^2----C_n^2}{n} }          II

By dividing II by I

P₀ = 2 P

Thus pressure will become double than its previous value

5 0
3 years ago
A military helicopter on a training mission is flying horizontally at a speed of 90.0 m/s when it accidentally drops a bomb (for
Elena-2011 [213]

Answer:

1) 10.1 s  2) 909 m 3) 90.0 m/s 4) -99m/s 5) just over the bomb.

Explanation:

1)

  • In the vertical direction, as the bomb is dropped, its initial velocity is 0.
  • So, we can find the time required for the bomb to reach the earth, applying the following kinematic equation for displacement:

       \Delta y = \frac{1}{2}*a*t^{2} (1)

  • where Δy = -500 m (taking the upward direction as positive).
  • a=-g=-9.8 m/s²
  • Replacing these values in (1), and solving for t, we have:

       t =\sqrt{\frac{2*\Delta y}{-g}} = \sqrt{\frac{2*(-500m)}{-9.8m/s2}} = 10.1 s

  • The time required for the bomb to reach the earth is 10.1 s.

2)

  • In the horizontal direction, once released from the helicopter, no external influence acts on the bomb, so it will continue moving forward at the same speed. that it had, equal to the helicopter.
  • As the time must be the same for both movements, we can find the horizontal displacement just as the product of this speed times the time, as follows:

       x = v_{0x} * t = 90.0 m/s * 10.1 s = 909 m.

3)

  • The horizontal component of the bomb's velocity is the same that it had when left the helicopter. i.e. 90 m/s.

4)

  • In order to find the vertical component of the bomb's velocity just before it strikes the earth, we can apply the definition of acceleration, remembering that v₀ = 0, as follows:

        v_{f} = -g*t = -9.8 m/s2*10.1 s = -99 m/s

5)

  • If the helicopter keeps flying horizontally at the same speed, it will be always over the bomb, as both travel horizontally at the same speed.
  • So, when the bomb hits the ground, the helicopter will be exactly over it.

8 0
3 years ago
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