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melomori [17]
3 years ago
7

An object is dropped near the earth's surface. At the end of 4.0 s, how fast is it falling in m/s? (Ignore air resistance.)

Physics
2 answers:
Sati [7]3 years ago
7 0
For free falling bodies, the final velocity may be calculated through the equation,
                                   Vf = gt
Where g is the acceleration due to gravity (9.8 m/s²) and t is the time elapsed. Substituting the known values,
                                   Vf = (9.8 m/s²) x (4 s) = 39.2 m/s
Therefore, the object's velocity is approximately 39.2 m/s. 
DochEvi [55]3 years ago
4 0

The answer would be 39.2 m/s

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Answer:

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Explanation:

Using the equations of motion

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g = (6.674 × 10⁻¹¹ × 5.97 × 10²⁴)/(6370000²)

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Hope this Helps!!!

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4 years ago
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