A semicircle is inscribed in an isosceles triangle with base 16 and height 15 so that the
1 answer:
Answer:
7 1/17
Step-by-step explanation:
A figure can be helpful.
The inscribed semicircle has its center at the midpoint of th base. It is tangent to the side of the isosceles triangle, so a radius makes a 90° angle there.
The long side of the isosceles triangle can be found from the Pythagorean theorem to be ...
BC² = BD² +CD²
BC² = 8² +15² = 289
BC = √289 = 17
The radius mentioned (DE) creates right triangles that are similar to ∆BCD. In particular, we have ...
(long side)/(hypotenuse) = DE/BD = CD/BC
DE = BD·CD/BC = 8·15/17
DE = 7 1/17 ≈ 7.059
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Answer: The complete question is found in the attachment
Step-by-step explanation:
a) To determine the 1-unit growth factor for <em>f</em>
= 2.1/1.75 = 1.2
b) To determine the 1-unit percent change for <em>f</em>
<em>=100 x 1-1.2/1 = 0.2 x 100= 20%</em>
<em>c) to determine the initial value of f</em>
<em>f(x)= abˣ , b =1.2 a=initial value</em>
<em>at (-1,2.1)</em>
<em>2.1= (1.2)⁻¹ x a</em>
<em>a = 2.1/(1.2)⁻¹ </em>
<em>a = 2.1 x 1.2 = 2.52</em>
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<em>d) to determine the function formula for f</em>
<em>f(x)= abˣ = 2.52(1.2)ˣ</em>
