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3 years ago

Find the area of the figure. please help my teacher is waiting.......

Mathematics

1 answer:

katrin [286]3 years ago

7 0

Answer:

The area of the shape is 89m²

Step-by-step explanation:

You need to subtract the area of the empty triangle from the area of the rectangle.

The rectangle's area is 13m × 8m = 104m²

The triangle's area is (6m × (13 - 8)m) / 2 = (6 × 5) / 2 m² = 15m²

Subtract the triangle's area from the rectangle:

104m² - 15m²

= 89m²

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2 years ago

Through(-2,-3); parallel to 3x+2y=5

Vilka [71]

Step-by-step explanation:

Hey there!

Firstly find slope of the given equation.

Given eqaution is: 3x + 2y = 5.......(i)

Now;

$slope(m1) = \frac{ - coeff. \: of \: x}{coeff. \: of \: y}$

$or \: m1 = \frac{ - 3}{2}$

Therefore, slope (m1) = -3/2.

As per the condition of parallel lines,

Slope of the 1st eqaution (m1) = Slope of the 2nd eqaution (m2) = -3/2.

The point is; (-2,-3). From the above solution we know that the slope is (-3/2). So, the eqaution of a line which passes through the point (-2,-3) is;

(y-y1) = m2 (x-x1)

~ Keep all values.

$(y + 3) = \frac{ - 3}{2} (x + 2)$

~ Simplify it.

$2(y + 3) = - 3x - 6$

$2y + 6 = - 3x - 6$

$3x + 2y + 12 = 0$

Therefore, the eqaution of the line which passes through the point (-2,-3) and parallel to 3x + 2y= 5 is 3x + 2y +12 =0.

Hope it helps...

8 0

2 years ago

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